According to a recent poll, 26% of adults in a certain area have high levels of cholesterol. They report that such elevated levels "could be financially devastating to the regions healthcare system" and are a major concern to health insurance providers. According to recent studies, cholesterol levels in healthy adults from the area average about208mg/dL, with a standard deviation of about 30 mg/dLand are roughly Normally distributed. Assume that the standard deviation of the recent studies is accurate enough to be used as the population standard deviation. If the cholesterol levels of a sample of 41 healthy adults from the region is taken, answer parts a through d. a) What shape will the sampling distribution of the meanhave? A. The sampling distribution of the mean is skewed right. B. The sampling distribution of the mean is skewed left. C. The sampling distribution of the mean is normal. D. There is not enough information to determine the shape of the sampling distribution. b) What is the mean of the sampling distribution? μ=enter your response here mg/dL c) What is the standard deviation? SD(y)=enter your response here mg/dL (Round to two decimal places as needed.)d) If the sample size were
According to a recent poll, 26% of adults in a certain area have high levels of cholesterol. They report that such elevated levels "could be financially devastating to the regions healthcare system" and are a major concern to health insurance providers. According to recent studies, cholesterol levels in healthy adults from the area average about208mg/dL, with a standard deviation of about 30 mg/dLand are roughly
41
healthy adults from the region is taken, answer parts a through d.
a) What shape will the sampling distribution of the meanhave?
A.
The sampling distribution of the mean is skewed right.
B.
The sampling distribution of the mean is skewed left.
C.
The sampling distribution of the mean is normal.
D.
There is not enough information to determine the shape of the sampling distribution.
b) What is the mean of the sampling distribution?
μ=enter your response here
mg/dL
c) What is the standard deviation?
SD(y)=enter your response here
mg/dL (Round to two decimal places as needed.)d) If the sample size were increased to
90,
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