Waiting Times24 54 61654 4752 204852401722 38183132936482 3411507 26 425052 153439 1532 45394 338 5 According to a 2017 survey by a reputable organization, patients had to wait an average of 24 days to schedule a newappointment with a doctor. A random sample of 40 patients in 2018 was selected and the number of days they had towait to schedule an appointment was recorded, with the accompanying results. Complete parts a and b.Click the icon to view the wait time data.a. Perform a hypothesis test using a = 0.01 to determine if the average number of days appointments are booked inadvance has changed since 2017.Determine the null and alternative hypotheses.HoiHH₁: H(Type integers or decimals. Do not round.)

From the provided information,Sample size (n) = 40Level of significance (α) = 0.01

Answered: According to a 2017 survey by a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 10 compact cars, 10 mid-size cars, and 10 luxury cars were selected. The time (in seconds) each of the randomly selected cars required to accelerate from 0 to 60 mph was looked up on the Autos.com website. The results are presented below. Car Type Time (in seconds) Required to Accelerate from 0 to 60 mph Compact 9.3 8.1 10.2 8.8 9.0 9.3 7.7 9.2 9.4 8.6 Mid-Size 6.9 5.7 8.3 7.7 8.6 5.9 6.1 8.8 6.1 7.2 Luxury 5.7 6.3 5.4 4.7 6.2 7.0 5.9 5.3 6.3 5.0 Conduct a hypothesis test using ! = 0.05 to determine whether the mean time required to accelerate from 0 to 60 mph is the same for compact, mid-size, and luxury cars. (No accounting or excel, I need help solving it.)
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According to the NIMH website the average number of adult Americans diagnosed with a “serious mental illness” across all 50 states in 2019 was μ = 5.2 out of 100 residents (or 5.2%). Please test to see if the sample of states listed below (n=8) has a significantly higher level of mental illness than the population mean of 5.2. Sample data: Arkansas= 5.45%, Montana=5.34%, Vermont=5.32%, Oregon=5.19%, Utah=5.2%, Ohio=5.13, Kentucky=5.25% West Virginia=5.18%. Hint - drop the % signs and use 5.45, 5.32, etc as the X scores. If you want you can use JASP for help with the calculations. Use 3 decimal places for the M, s, SEM. The alpha level for the study was set to α=.05. a. State the hypotheses of the study. b. Find the critical t value for this studyc. Compute the one-sample t test. d. Compute the Cohen's d for the data (even if not significant) e. State the results - is the sample significantly higher? Do you reject the null hypothesis? Report the t test results in APA format…

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