Answered: Acceleration = -4.6332 m/s^2 Mass of… | bartleby

Related questions

Question

Question
Acceleration = -4.6332 m/s^2
Mass of cart = 512.2 g
Mass of hanging object = 250 g
What is the coefficient of kinetic friction between
the upside down cart and the track

COURT (512.29)
A
هم
Track
string
object
(250g)

Expert Solution

Step 1

Solution:

The given acceleration and mass are the following:

$a = 4.6 m / s^{2} m_{c} = 512.2 g m = 250 g$

Let T be the tension in the string. Then the equation of motion of the cart is,

$T - f_{k} = m_{c} a T - μ_{k} m_{c} g = m_{c} a . . . . . . (1) μ_{k} - c o e f f i c i e n t o f k i n e t i c f r i c t i o n .$

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A car travels around a horizontal bend of radius 110 m at a constant speed. If the coefficient of the static friction between the road and car tyres is us = 7.4, What is the magnitude of car's acceleration (m/s²) when the car is negotiating ?the bend at the maximum allowed speed
A ball is falling through air. Calculate the terminal speed (a positive number, in m/s) if these are the parameters: m = 3 kg b = 1 N/(m/s) g = 10 m/s2
= A curve that has a radius of 95 m is banked at an angle of 0 10.0°. If a 1050 kg car navigates the curve at 70 km/h without skidding, what is the minimum coefficient of static friction Ms between the pavement and the tires? Ms =
A car is rounding a turn on a road that is banked at some angle with respect to the horizontal. The road is covered with ice and there is no friction between the road and the tires. which of the following forces is responsible for keeping the car on its circular path? The horizontal component of the force of gravity It is impossible for the car to stay on a circular path in this situation The vertical component of the force of gravity The horizontal component of the normal force The vertical component of the normal force Complete the following sentence. Centripetal forces enable objects to follow circular trajectories with constant speed. enable objects to follow circular trajectories with constant acceleration. O are described by Hooke's law for springs. double in magnitude when an object's speed in uniform circular motion is doubled. OOOO
A 20-ton truck collides with a 1500-lb car and causes a lot of damage to the car. During the collision × the force that the truck exerts on the car is much greater than the force that the car exerts on the truck the car and the truck have the same magnitude acceleration. the force that the car exerts on the truck is slightly greater than the force that the truck exerts on the car the force that the car exerts on the truck is exactly equal to the force that the truck exerts on the car
You need to cross a river but you don't care where you land on the other side. Question 2 options: You will cross faster if you swim into the current so you do not drift. the fastest way across is to swim at an angle to the current You cannot change the rate you cross the river by swimming in any direction the fastest way to cross is to point straight across the river
q20
Multiple-object systems without friction: Three objects are connected by massless wires over a massless frictionless pulley as shown in the figure. The tension in the wire connecting the 10.0-kg and 15.0-kg objects is measured to be 133 N. What is the mass M? (52.8 kg) Σ 15.00 kg 133 N 10.00 kg
35. A small block slides along the inside of a frictionless vertical circular track. At the high point of the motion the block's acceleration has magnitude 2g. What is the magnitude of the block's acceleration at the low point? a) 6g ☐ b) 5g c) 4g d) 3g e) 2g (numbers 36-37) An object's position versus time graph is shown.
A car is traveling at 15 m/s on a horizontal road. The brakes are applied and the car skids to a stop in 4.0 s. The coefficient of kinetic friction between the tires and road is: Friction Road Direction of travel