Acar battery has a range that follows an approximately Normal distribution with mean 700 km and standard deviation 44 km. For a random sample of 31 batteries, the average range is found to be 690 km. Test the hypothesis u= 700 km againstH#700 km by using the P-value of the test (assume a= 0.05). [Refer to appropriate distribution table if needed.]O A. Test value: - 1.27, P-value: 0.103, Test result: Reject HoOB. Test value: 1.27, P-value: 0.103, Test result: Reject HnOC. Test value: 1.27, P-value: 0.206, Test result: Do not reject HnOD. Test value: - 1.27, P-value: 0.206, Test result: Do not reject Ho

Given, X~N( 700,442 ) n=31 sample mean=690

Acar battery has a range that follows an approximately Normal distribution with mean 700 km and standard deviation 44 km. For a random sample of 31 batteries, the average range is found to be 690 km. Test the hypothesis u= 700 km again H#700 km by using the P-value of the test (assume o = 0.05). [Refer to appropriate distribution table if needed.] O A. Testvalue: -1.27, P-value: 0.103, Test result: Reject Ho OB. Testvalue: 1.27, P-value: 0.103, Test result: Reject Ho OC. Testvalue: 1.27, P-value: 0.206, Test result: Do not reject Ho OD. Test value: - 1.27, P-value: 0.206, Test result: Do not reject Ho

Acar battery has a range that follows an approximately Normal distribution with mean 700 km and standard deviation 44 km. For a random sample of 31 batteries, the average range is found to be 690 km. Test the hypothesis u= 700 km again H#700 km by using the P-value of the test (assume o = 0.05). [Refer to appropriate distribution table if needed.] O A. Testvalue: -1.27, P-value: 0.103, Test result: Reject Ho OB. Testvalue: 1.27, P-value: 0.103, Test result: Reject Ho OC. Testvalue: 1.27, P-value: 0.206, Test result: Do not reject Ho OD. Test value: - 1.27, P-value: 0.206, Test result: Do not reject Ho

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A standardized math test of fifth grade students produces a mean ?μ = 100 with a ?σ = 18. A sample of n = 36 students participated in "boost" training for their math skills. The sample M = 104 with S = 24. Did this "boost" training significantly improve students' math performance? Use ?α = .01.
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
Babies: A sample of 25 one-year-old girls had a mean weight of 24.1 pounds with a standard deviation of 4.3 pounds. Assume that the population of weights is normally distributed. A pediatrician claims that the standard deviation of the weights of one-year-old girls is greater than 7 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the =α0.05 level of significance.
This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
solve
Erin is a nutritionist and cardiologist. She is testing whether the average total cholesterol level of adults in the region is less than 175mgdL. Erin randomly selects 25 people in the region who willingly allowed their blood to be drawn for the survey. Based on several previous studies, Erin assumes that the population standard deviation for the total cholesterol level is 30.22mgdL. For this test: H0:μ=175; Ha:μ<175, which is a left-tailed test. The test results are: z0=−1.158, p-value is = 0.123 Using a 5% level of significance, which of the following are appropriate conclusions for this hypothesis test? Select all that apply. Select all that apply: We reject H0. We fail to reject H0. At the 5% significance level, the data provide sufficient evidence to conclude that the average total cholesterol level of adults in the region is less than 175mgdL. At the 5% significance level, the data do not provide sufficient evidence to conclude that…
number 7 and 8 pls
A survey found that the average hotel room rates and standard deviations for the state of Arkansas and the state of Washington. Assume that the data were obtained from two samples were normally distributed. At a=0.1 level of significance, can it be concluded that there is a significant difference in the rates? Use the data table below. Report only the value required from the question below make sure to express your final answers in 4 decimal places. Parameter Arkansas Washington Sample size 82.00 72.00 sample 350.46 360.01 mean population standard deviation 29.17 27.20 a. Variance of Arkansas:
Answer the exercise of the image. (In the other image are the final answers, this to verify the final answer).
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.3 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 1030 samples is 5.4 ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.01 level? Step 4 of 5 : Enter the decision rule.
Compute the range and sample standard deviation for strength of the concrete (in psi). 3910, 4090, 3500, 3100, 2940, 3830, 4090, 4040
A distribution of values is normal with a mean of 41.2 and a standard deviation of 24.2. Find P38, which is the score separating the bottom 38% from the top 62%. P38 = Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Submit Question abc esc F1 F2 F3 F4 F5 F6 %23 3. Q W R 454