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Provide an explanation of the effects which are responsible for the three absorbances profile in relation to the height of the burner. Figure below shows the absorbance profile of the three elements.
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- You prepare several dilutions of an unknown compound. You measure the absorbance of each solution at 340 nm using a 1 cm cuvette (your results are listed in the table below). What is the extinction coefficient (in (Mecm) ') of the compound? (Hint: assume that each of the individual values contains some degree of experimental error.) Concentration(uM) Absorbance at 340 nm 10.0 0.011 20.0 0.023 40.0 0.066 80.0 0.119 160.0 0.189The absorbance of an unknown dye solution is measured to be 1.06 by a spectrometer. The calibration plot of the spectrometer is provided below. What is the molar concentration of the unknown sample (in mole L)? Absorbance vs. Molarity 18 y3 67024x-0.0343 16 14 12 1 0.8 0.6 0.4 0.2 01 0.2 0.000005 00001 0000015 Concentration of solutions, mol/L 0.00002 0.000025 000003 0 163e-5 O 2.35e-6 0 163 0 235 Absorbance9
- Yellow Dye Calibration Curve y = 254.78x - 0.1414 R? = 0.9792 2.5 1.5 1 0.5 0.002 0.004 0.006 0.008 0.01 0.012 Concentration(M) 3. 2. AbsorbanceDuring your experiment, you measure the absorbance of a sample to be 1.362. You have to convert thisabsorbance to methylene blue concentration (in ppm) using the absorbance measurements of two standardsolutions of known concentration:5 ppm: Absorbance 0.55510 ppm: Absorbance 1.211What is, in ppm, the concentration of your sample? Report using 3 decimal figures. Your answer must becorrect to 0.02 ppmA solution with %T = 75.9% has an absorbance equal to: A = log (1 T) T= (% T 100)
- .Q1. To determine the concentrations (mol/L) of Co(NO3)2 (A) and Cr(NO3)3(B) in an unknown sample, the following representative absorbance data wereobtained.A (mol/L) B (mol/L) 510nm 575nm5×10−1 0 0.714 0.0970 6×10−2 0.298 0.757Unknown Unknown 0.671 0.330Measurements were made in 1.0 cm glass cells.i. Calculate the four molar absorptivities: ∈A(510), ∈A(575), ∈B(510) and ∈B(575).ii. Calculate the molarities of the two salts A and B in the unknown.An impurity in water has an extinction coefficient of 3.45 * 103 M-1 cm-1 at 280 nm, its absorption maximum(A Closer Look, p. 576). Below 50 ppb, the impurity is not a problem for human health. Given that most spectrometers cannot detect absorbances less than 0.0001 with good reliability, is measuring the absorbance of a water sample at 280 nm a good way to detect concentrations of the impurity above the 50-ppb threshold?This question has multiple parts. Work all the parts to get the most points. A solution of a dye was analyzed by spectrophotometry, and the following calibration data were collected. Dye Concentration Absorbance (A) at 475 nm 0.50 x 10 M 0.24 9. 1.5 x 10 M 0.36 2.5 x 10 M 3.5 x 10 M 4.5 x 10 M 0.44 0.59 0.70 a Construct a calibration plot, and determine the slope and intercept. Slope = y-intercept =
- A student prepared four standard solutions of (NH4)2Fe(SO4)2 and measured their absorbance at 505 nm. She created a calibration plot with the best-fit line of y = 9372 x + 0.0539. She measured the absorbance of her diluted unknown sample solution as (4.69x10^-1) nm. If she prepared her diluted sample solution by diluting 10.00 mL of the original solution to a total volume of 50.00 mL with deionized water, what is the concentration of Fe2+ in her original solution? Answer in units of M. Note: Your answer is assumed to be reduced to the highest power possible.The spectroscopic data in the table is generated with five solutions of known concentration. Concentration (M) 0.0133 m= 0.0266 0.0532 0.106 0.213 Absorbance 0.1271 What is the intercept of the linear regression line? 0.08531 0.5388 1.069 Use a spreadsheet program, such as Microsoft Excel, to graph the data points and determine the equation of the best-fit line. 1.954 What is the slope of the linear regression line formed by these points? M-1A solution of potassium permanganate of unknown concentration was analyzed against a standard of various concentrations. Refer to the following data set to answer the succeeding questions (MM KMNO4 = 158.034 g/mol). Table 1. Data for Standard Calibration Curve KMN04 Standard Absorbance at 525 nm (grams/Liter) 0.008 0.10437 0.158 0.20197 0.316 0.45288 0.474 0.68232 0.632 0.89361 Table 2. Data for KMNO4 Solution of Unknown Conc. Sample of Unknown Absorbance at 525 nm Conc. Undiluted 0.95423 KMN04 Diluted KMNO4 0.46514 (50% dilution) Which of the following linear equation for the standard calibration curve is generated from Table 1? y= 0.74923x – 0.03231 y= 0.03231x –0.74923 y= 1.3179x + 0.04845 y= 0.04848x + 1.3179 O O O