absolute configuration cop 9 d figuration of the the third contre J-R 3-S J-R, 3-R 5 32-5, 3-5 2-5, 3-R 4 sical coomerinn as well as optical a which can show geometrical 1-CH=C = CHIC C=C=C=C3 CH₂ Calz 10.55 belongs to 1-

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A: To choose the correct hybridization of chiral center

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A: 3rd ,4th and 5th compound are chiral , this can be explained as:

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Q: otate it back or use the "switch method") I. -H II. I. is R, II. is R

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Q: (+) O

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Q: None

A: From your description:G: CH(CH3)2H: H3CLet's interpret these structures:G: CH(CH3)2This indicates a…

Q: None

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A: we will be doing the conformational analysis of the given molecule.

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A: Carbon atom having four different groups attached is known as s stereo centre or chiral centre.

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