Answered: --- About initial programming in python…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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--- About initial programming in python ---

Make a procedure called many_times() that simulates
a game of two dice. Your procedure should count how many times
the dice were rolled until repeated numbers came out. (To throw
two dice count as a single throw.) What should your procedure return? Should return the number of throws made and the two [equal] numbers chosen --- put the three values into a tuple. Suppose your dice has 6 sides. Use the randint procedure of the random module to simulate the throw of a die. Documents for this procedure can be found at https://cutt.ly/dWsa2Rl. Note that there are restrictions on input values.
Use randint, tuples and while to solve the problem.

REMEMBER THAT THE THIRD ELEMENT IN THE TUPLE (THE NUMBER OF THROWS MADE) CANNOT BE 0

- Below is a print of my code that you should use as a basis to solve the challenge. My problem is that the third element of my tuple (number of dice rolls until repeated numbers appear) is returning 0 in some situations which is obviously wrong.

>>> how_many ()
(4, 4, 0)
>>> how many ()
(4, 4, 1)
>>> how many ()
(5, 5, 4)
>>> how many ()
(6, 6, 0)
>>> how many ()
(1, 1, 4)
>>> how many ()
(2, 2, 6)
import random
def how many () :
count = 0
while True:
x = random.randint (1, 6)
y = random.randint (1, 6)
if x == y:
break
else:
count+=1
return tuple ( (x,y, count))
>>>

Expert Solution

Step 1

I have implemented the given requirements as above.

The issue is that there is no check for the value of count. There should be an "if" condition which checks if the value of count is greater than 0. Only in that case it will return the tuple.

The case where count is 0 is when the two dice rolled repeated number in the first throw which is to be ignored.

Code is as follows:

import random

def how_many():

count = 0

while True:

x = random.randint(1, 6)

y = random.randint(1, 6)

if(x == y):

break

else:

count = count + 1