About 73% of all female heart transplant patients will survive for at least 3 years. Sixty female heart transplant patients are randomly selected. What is the probability that the sample proportion surviving for at least 3 years will be less than 68%? Assume the sampling distribution of sample proportions is a normal distribution. The mean of the sample proportion is equal to the population proportion and the standard deviation is equal to The probability that the sample proportion surviving for at least years will be less than 68% is |. (Round to four decimal places as needed.)

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### Probability in Female Heart Transplant Survival Rates

**Problem Statement:**

About 73% of all female heart transplant patients will survive for at least 3 years. Sixty female heart transplant patients are randomly selected. What is the probability that the sample proportion surviving for at least 3 years will be less than 68%? Assume the sampling distribution of sample proportions is a normal distribution. The mean of the sample proportion is equal to the population proportion and the standard deviation is equal to \(\frac{\sqrt{pq}}{\sqrt{n}}\).

**Formula Explanation:**

\[
\text{Standard deviation} = \frac{\sqrt{pq}}{\sqrt{n}}
\]

**Question to be Solved:**

The probability that the sample proportion surviving for at least 3 years will be less than 68% is \( \boxed{\hspace{1.25cm}} \). (Round to four decimal places as needed.)

---

This exercise demonstrates the application of the normal distribution in determining the probability of a specific sample proportion when given population parameters. It requires the knowledge of calculating the standard deviation for sample proportions and interpreting probabilities from the normal distribution.
Transcribed Image Text:### Probability in Female Heart Transplant Survival Rates **Problem Statement:** About 73% of all female heart transplant patients will survive for at least 3 years. Sixty female heart transplant patients are randomly selected. What is the probability that the sample proportion surviving for at least 3 years will be less than 68%? Assume the sampling distribution of sample proportions is a normal distribution. The mean of the sample proportion is equal to the population proportion and the standard deviation is equal to \(\frac{\sqrt{pq}}{\sqrt{n}}\). **Formula Explanation:** \[ \text{Standard deviation} = \frac{\sqrt{pq}}{\sqrt{n}} \] **Question to be Solved:** The probability that the sample proportion surviving for at least 3 years will be less than 68% is \( \boxed{\hspace{1.25cm}} \). (Round to four decimal places as needed.) --- This exercise demonstrates the application of the normal distribution in determining the probability of a specific sample proportion when given population parameters. It requires the knowledge of calculating the standard deviation for sample proportions and interpreting probabilities from the normal distribution.
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