Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
![ABCD is a kite, so AC 1 DB and
DE = EB. Calculate the length of AC,
to the nearest tenth of a centimeter.
D
8 cm
5 cm
E
A
-8 cm-
C
В](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb6a3e0a-0e9e-4eb9-b3f8-cac67ff0b1b6%2F72e3f4b8-b4d1-4298-bf18-8d045b658959%2Fg33edvc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ABCD is a kite, so AC 1 DB and
DE = EB. Calculate the length of AC,
to the nearest tenth of a centimeter.
D
8 cm
5 cm
E
A
-8 cm-
C
В
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Follow-up Questions
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Follow-up Question
∴ AC¯ = AE¯+EC¯ = 43+3 ≈ 9.9
9.79 and if u round to the nearest 10th it out be 9.8 and not 9.9
![ABCD is a kite, so AC 1 DB and
DE = EB. Calculate the length of AC,
to the nearest tenth of a centimeter.
D
8 cm
5 cm
E
A
-8 cm-
C
В](https://content.bartleby.com/qna-images/question/eb6a3e0a-0e9e-4eb9-b3f8-cac67ff0b1b6/b8ac1288-448e-4d69-93d3-c8f5162f8348/n059jm_thumbnail.jpeg)
Transcribed Image Text:ABCD is a kite, so AC 1 DB and
DE = EB. Calculate the length of AC,
to the nearest tenth of a centimeter.
D
8 cm
5 cm
E
A
-8 cm-
C
В
Solution
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