ABC is a right-angled triangle at A and AB > AC. Bisect BC in D draw DE perpendicular to the hypotenuse BC to meet the bisector of the right angle A in E. Prove that (i) AD = DE; (i) /DAE = } (2C – ZB). CONSTRUCTION: Draw AF BC (Fig. %3D A В F O D E

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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ABC is a right-angled triangle at A and AB > AC. Bisect BC in D
draw DE perpendicular to the hypotenuse BC to meet the bisector of the right
angle A in E. Prove that (i) AD =
CONSTRUCTION: Draw AF | BC (Fig.
DE; (ii) LDAE = } (2C – ZB).
%3D
|
A
В
F O
D
Transcribed Image Text:ABC is a right-angled triangle at A and AB > AC. Bisect BC in D draw DE perpendicular to the hypotenuse BC to meet the bisector of the right angle A in E. Prove that (i) AD = CONSTRUCTION: Draw AF | BC (Fig. DE; (ii) LDAE = } (2C – ZB). %3D | A В F O D
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