A,B, and Care midpoints of sides DF.DE,& FE respectively. If BC-11, AC=13, and AB=15, find the perimeter ofADEF F

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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### Geometry Problem on Triangle Perimeters

**Problem Statement:**
A, B, and C are midpoints of sides DF, DE, and FE respectively. If BC = 11, AC = 13, and AB = 15, find the perimeter of triangle DEF (ΔDEF).

**Given Diagram Description:**
The diagram displays a triangle DEF with:
- Triangles within it connecting midpoints A, B, and C to form a smaller inner triangle.
- Points A, B, and C are indicated to be the midpoints of the sides DF, DE, and FE respectively.
- Line segments BC, AC, and AB are highlighted.

**Solution:**
The perimeter of triangle DEF can be determined by noting that A, B, and C are midpoints, bisecting the sides of DEF. Given:
- BC = 11
- AC = 13
- AB = 15

Since A, B, and C are midpoints of DF, DE, and EF respectively, each segment of DEF is twice the corresponding segment of the smaller triangle ABC. Therefore:
- DF = 2 × AB = 2 × 15 = 30
- DE = 2 × AC = 2 × 13 = 26
- EF = 2 × BC = 2 × 11 = 22

The perimeter of ΔDEF:
\[ \text{Perimeter} = DF + DE + EF \]
\[ \text{Perimeter} = 30 + 26 + 22 \]
\[ \text{Perimeter} = 78 \]

Thus, the perimeter of triangle DEF is **78** units.
Transcribed Image Text:### Geometry Problem on Triangle Perimeters **Problem Statement:** A, B, and C are midpoints of sides DF, DE, and FE respectively. If BC = 11, AC = 13, and AB = 15, find the perimeter of triangle DEF (ΔDEF). **Given Diagram Description:** The diagram displays a triangle DEF with: - Triangles within it connecting midpoints A, B, and C to form a smaller inner triangle. - Points A, B, and C are indicated to be the midpoints of the sides DF, DE, and FE respectively. - Line segments BC, AC, and AB are highlighted. **Solution:** The perimeter of triangle DEF can be determined by noting that A, B, and C are midpoints, bisecting the sides of DEF. Given: - BC = 11 - AC = 13 - AB = 15 Since A, B, and C are midpoints of DF, DE, and EF respectively, each segment of DEF is twice the corresponding segment of the smaller triangle ABC. Therefore: - DF = 2 × AB = 2 × 15 = 30 - DE = 2 × AC = 2 × 13 = 26 - EF = 2 × BC = 2 × 11 = 22 The perimeter of ΔDEF: \[ \text{Perimeter} = DF + DE + EF \] \[ \text{Perimeter} = 30 + 26 + 22 \] \[ \text{Perimeter} = 78 \] Thus, the perimeter of triangle DEF is **78** units.
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