aaing 1 14) Ajar contains four red marbles, two white marbles, and three blue marbles. Without looking a student draws one marbie from the jar. What is the Dictate probability that the marble drawn is blúe? 1 A) C) 3
aaing 1 14) Ajar contains four red marbles, two white marbles, and three blue marbles. Without looking a student draws one marbie from the jar. What is the Dictate probability that the marble drawn is blúe? 1 A) C) 3
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![### Probability Question
**Question:**
A jar contains four red marbles, two white marbles, and three blue marbles. Without looking, a student draws one marble from the jar. What is the probability that the marble drawn is blue?
**Options:**
- A) 1/2
- B) 1/9
- C) 1/3
- D) 3/9
**Explanation:**
To solve this, we first need to determine the total number of marbles:
- Red marbles = 4
- White marbles = 2
- Blue marbles = 3
Total number of marbles = 4 (Red) + 2 (White) + 3 (Blue) = 9 marbles
The probability of drawing a blue marble is the number of blue marbles divided by the total number of marbles. Therefore, the probability P can be calculated as:
\[ P(\text{Blue marble}) = \frac{\text{Number of blue marbles}}{\text{Total number of marbles}} = \frac{3}{9} = \frac{1}{3} \]
Thus, the correct option is:
- C) 1/3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f7d7044-9e73-4878-b5e2-b5e6e505f8cb%2F3ae0f281-57d3-42dc-91bb-10ad26e0f055%2Ff1x0aal_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Probability Question
**Question:**
A jar contains four red marbles, two white marbles, and three blue marbles. Without looking, a student draws one marble from the jar. What is the probability that the marble drawn is blue?
**Options:**
- A) 1/2
- B) 1/9
- C) 1/3
- D) 3/9
**Explanation:**
To solve this, we first need to determine the total number of marbles:
- Red marbles = 4
- White marbles = 2
- Blue marbles = 3
Total number of marbles = 4 (Red) + 2 (White) + 3 (Blue) = 9 marbles
The probability of drawing a blue marble is the number of blue marbles divided by the total number of marbles. Therefore, the probability P can be calculated as:
\[ P(\text{Blue marble}) = \frac{\text{Number of blue marbles}}{\text{Total number of marbles}} = \frac{3}{9} = \frac{1}{3} \]
Thus, the correct option is:
- C) 1/3
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