067/assessments/233776/variants/325135/take/6Q ☆AABC has vertices A(-4,6), B(-6, – 4), and C(2, - 2).The following transformation defines AA"'B""C''':AA''B''C'"" = Rx-axis(TiT(2.3)/D.(ABC)Choose each correct coordinate for the vertices of AA""B''C'"'.Point A"Point B"Point C"O A" (-1,-4.5) O OC" (2,–0.5)O A" (-1,–1.5) OB" (-1,5) OC"(2,2.5)O B" (-2,0.5) O C" (3, –2)OB" (-2,3.5) O C" (3,4)B"(-1,-1)O C" (2,-0.5)O A" (0,-6)O A" (0,0)

Answered: AABC has vertices A(-4,6), B(-6, – 4),…

Elementary Geometry For College Students, 7e

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067/assessments/233776/variants/325135/take/6
Q ☆
AABC has vertices A(-4,6), B(-6, – 4), and C(2, - 2).
The following transformation defines AA"'B""C''':
AA''B''C'"" = Rx-axis(T
iT(2.3)/D.(ABC)
Choose each correct coordinate for the vertices of AA""B''C'"'.
Point A"
Point B"
Point C"
O A" (-1,-4.5) O OC" (2,–0.5)
O A" (-1,–1.5) OB" (-1,5) OC"(2,2.5)
O B" (-2,0.5) O C" (3, –2)
OB" (-2,3.5) O C" (3,4)
B"(-1,-1)
O C" (2,-0.5)
O A" (0,-6)
O A" (0,0)

Expert Solution

Step 1

Given data:

The first coordinate given is A(-4, 6).

The second coordinate given is B(-6, -4).

The third coordinate given is C(2, -2).

The expression for the dilation D_1/2 is,

$D_{\frac{1}{2}} (∆ A B C) = \frac{1}{2} (∆ A B C)$

Substitute the given values in the above expression.

$\begin{array}{rcl} D_{\frac{1}{2}} (∆ A B C) & = & A' (- 2, 3) \\ = & B' (- 3, - 2) \\ = & C' (1, - 1) \end{array}$

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AABC has vertices A(-4,6), B(-6, – 4), and C(2, -2). The following transformation defines AA""B"'C'"': AA''B'"'C'"" = Rx-axis(T(2,3) Choose each correct coordinate for the vertices of AA""B'"'C'"'.