AABC has acute angles and point X is inside AABC. Points P and R are on AB, points T and Q are on BC, and points S and U are on CA so that PQ passes through X and is parallel to AC, RS passes through X and is parallel to BC, and TU passes through X is parallel to BA. Prove that √^ABC| = √|^XPR|+√|AXQT|+√|AXSU|.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please don't assume that ABC is equilateral triangle because it is not given that it is equilateral.

 
AABC has acute angles and point X is inside AABC. Points P and R are on AB, points T
and Q are on BC, and points S and U are on CA so that PQ passes through X and is parallel
to AC, RS passes through X and is parallel to BC, and TU passes through X is parallel to
BA. Prove that √AABC| = √√|AXPR| + √|AXQT| + √|ÄXSU|.
Transcribed Image Text:AABC has acute angles and point X is inside AABC. Points P and R are on AB, points T and Q are on BC, and points S and U are on CA so that PQ passes through X and is parallel to AC, RS passes through X and is parallel to BC, and TU passes through X is parallel to BA. Prove that √AABC| = √√|AXPR| + √|AXQT| + √|ÄXSU|.
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