a)A particle of charge qA = +6nC at point A is located at rA = <2,-5,0>cm. What is the electric field EA due to this particle at the origin <0,0,0>cm? b) A second particle of charge qB = -6nC is placed at location B. The total electric field at the origin is now E = <-1E-4,0,0> N/C. Determine the location of point B(i.e. find rB) Hint: Drawing a diagram and treating the charges at points A and B as a dipole may help simplify this problem.

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.