A6m cantilever 200x500 rectangular beam is carrying a uniformly varying downward load of 0 kN/m at the tree end to 184 kN/m at the fixed end. There is an upward load of 312 kN at the free end. If the allowable flexural stress of the beam is 120 MPa and if the beam is to carry only a uniformly distributed load in kN/m. determine the safest uniform load that it can carry.

A6m cantilever 200x500 rectangular beam is carrying a uniformly varying downward load of 0 kN/m at the tree end to 184 kN/m at the fixed end. There is an upward load of 312 kN at the free end. If the allowable flexural stress of the beam is 120 MPa and if the beam is to carry only a uniformly distributed load in kN/m. determine the safest uniform load that it can carry.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A lightweight reinforced concrete beam is 400 mm and 630 mm deep.The beam is simplysupported over a span of 7.7 m and carries a uniform dead load of 12 kN/m excluding its ownweight and a uniform live load of 12 kN/m. The beam is reinforced for tension only with six-28mm diameter bars with an effective depth to tension bars of 570 mm. fc’=20.7 Mpa, fy=344.8Mpa. Modulus of Elasticity of Concrete, Ec = 21,750 Mpa and Es = 200 GPa a. Calculate the maximum instantaneous deflection due to service loads. b. Calculate the deflection for the same loads after five years assuming that 50% of thelive load is sustained.
A T-beam for a floor system has a slab thickness of 75 mm and a web thickness of 375 mm. It has an effective depth of 600 mm. The beam carries a dead load moment of 280 kN-m and a live load moment of 525 kN-m. It has a span of 5.4 m and a spacing center to center of 1.8 m. Use reduction factor ø=0.90, fc’=20.7 MPa, fy = 344.7 MPa.Determine the effective width of flange. Determine depth of compression flange. Determine the required steel area. See the formula in the image
A reinforced beam of size 300 mm × 450 mm and an effective depth of 400 mm is subjected to a working shear force of 100 kN. The beam is made up of M 25 concrete and Fe 415 steel. Determine the nominal shear stress (N/mm2)
An Am. long beam is on hinged at its left end and on fixed support at its right end. Its flexural capacity is 610 kN.m. whilte its web shear capacity is 642 kN. Beam flexural rigidity is Y x 1012 N.mm². #1 What is the allowable uniformly distributed load on the beam so that the flexural capacity is not exceeded? #2 Based on web shear capacity, what is the allowable uniformly distributed load (kN/m)? #3 When the support at the left end is removed, a cantilever beam results. How much should the beam be cambered at the free end to offset the end deflection if the load W = 210 kN/m? Use: A = 8 Y=29
The steel beam has the cross section shown. The beam length is L = 7.3 m, and the cross-sectional dimensions are d = 300 mm, bf = 180 mm, tf = 13 mm, and tw = 7 mm. Calculate the largest intensity of distributed load w0 that can be supported by this beam if the allowable bending stress is 250 MPa.
1.) A beam carries the loading shown. Design a rectangular timber beam if the permissible stresses are 120 Mpa in tension and compression, and 100 Mpa in shear. 20 kN/m 50 kN A B 6 m + 2m
SHOW COMPLETE SOLUTION AND DRAW THE FBD.
A Universal beam of I shaped cross-section is 203 mm deep, and 133 mm wide and has a steel plate 150 mm by 10 mm thick fastened to each flange. Ix-x for the universal beam is 28.80×10^6 mm^4. a) Determine the total uniformity distributed load which may be carried over a simply supported span of 6 metres if the permissible bending stress is 165 N/mm^2. Neglect the self-weight of the beam. [Ans.: 124.02 KN/m] b) Determine the minimum central length over which the additional plates are required. [Ans.: 4.23m]
Situation 11 An overhang beam is loaded as shown below. The beam cross-section was built by attaching two (2) channels to a 9mm thick plate using 16mm rivets The property of the channel is given below: Depth, D=225 mm Flange Width, B=112.5 mm. Flange Thickness, tf=9mm Web Thickness, tw9 mm The allowable flexural stress on the beam is 180 MPa. Rivets has a capacity of t 100 MPa on shear, for bearing, o.-200 MPa on single sheer, a-260MPa on double shear. 2. Determine the moment of inertia, I, of the section in mm^4.
An 8 m simply supported beam supports a uniformly distributed load of w and a 3kN concentrated load located at midspan. The beam's cross section is found to be an inverted triangle with base of 350mm and a height of 400 mm. If the allowable stresses are 90MPa, 30MPa and 2MPa for Fb₁, Fbc, and Fv respectively, solve for the value of w.