A6. Given: AABC has AB = BC. Point P is on AB and Q is on BC such that AP = CQ. Prove: CP= AQ. Make your own picture! 7. Refer to the figure at right. Prove: If DEL PF, then m/1> mZD. D P 1 E 8. Prove the () part of the Perpendicular Bisector Theorem: Referring to the figure with the theorem, prove that if PT is the perpendicular bisector of AB, then PA= PB.
A6. Given: AABC has AB = BC. Point P is on AB and Q is on BC such that AP = CQ. Prove: CP= AQ. Make your own picture! 7. Refer to the figure at right. Prove: If DEL PF, then m/1> mZD. D P 1 E 8. Prove the () part of the Perpendicular Bisector Theorem: Referring to the figure with the theorem, prove that if PT is the perpendicular bisector of AB, then PA= PB.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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