A6. Given: AABC has AB = BC. Point P is on AB and Q is on BC such that AP = CQ. Prove: CP= AQ. Make your own picture! 7. Refer to the figure at right. Prove: If DEL PF, then m/1> mZD. D P 1 E 8. Prove the () part of the Perpendicular Bisector Theorem: Referring to the figure with the theorem, prove that if PT is the perpendicular bisector of AB, then PA= PB.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Could someone please help me with problem 6 & 8 please and thank you!

6. Given: AABC has AB
Prove: CP= AQ. Make your own picture!
=
8.
8.
BC. Point P is on AB and Q is on BC such that AP = CQ.
7. Refer to the figure at right.
Prove: If DEL PF, then m/1> mZD.
P. 1
E
F
Prove the () part of the Perpendicular Bisector Theorem: Referring to the figure with the theorem,
prove that if PT is the perpendicular bisector of AB, then PA = PB.
Transcribed Image Text:6. Given: AABC has AB Prove: CP= AQ. Make your own picture! = 8. 8. BC. Point P is on AB and Q is on BC such that AP = CQ. 7. Refer to the figure at right. Prove: If DEL PF, then m/1> mZD. P. 1 E F Prove the () part of the Perpendicular Bisector Theorem: Referring to the figure with the theorem, prove that if PT is the perpendicular bisector of AB, then PA = PB.
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