A5) A projectile is given a velocity vo. Detemine the angle o at which it should be launched so that d is a maximum. The acceleration due to gravity is g.

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A5) A projectile is given a velocity v,. Determine the
angle o at which it should be launched so that d is a
maximum. The acceleration due to gravity is g.
-) x = xo + (vo)xt
. d cos e = 0+ vo cos ot
d cos e
-(1)
:t =
vo cos ¢
1
1) y = yo + (vo)yt +at²
i d sin e = 0+ vo sin ot +(-g)t –-- (2)
d cos 0
d cos e
Substitute (1)into (2): d sin e = v, sin o
vo cos o
Vo cos o
(sin 20 – 2 tan e cos² 4)
g cos e
* d =
Vir d 'n maksimum:
d(d)
= 0
dø
d(d)
(cos 20 (2) – 2 tan 8 (2 cos p)(- sin o))
= 0 =
dø
:: (cos 2¢ + tan e sin 20) = 0
: (1+ tan e tan 20) = 0
g cos e
==tan- (-)
: tan 20
= -
tan e
tan e
Transcribed Image Text:A5) A projectile is given a velocity v,. Determine the angle o at which it should be launched so that d is a maximum. The acceleration due to gravity is g. -) x = xo + (vo)xt . d cos e = 0+ vo cos ot d cos e -(1) :t = vo cos ¢ 1 1) y = yo + (vo)yt +at² i d sin e = 0+ vo sin ot +(-g)t –-- (2) d cos 0 d cos e Substitute (1)into (2): d sin e = v, sin o vo cos o Vo cos o (sin 20 – 2 tan e cos² 4) g cos e * d = Vir d 'n maksimum: d(d) = 0 dø d(d) (cos 20 (2) – 2 tan 8 (2 cos p)(- sin o)) = 0 = dø :: (cos 2¢ + tan e sin 20) = 0 : (1+ tan e tan 20) = 0 g cos e ==tan- (-) : tan 20 = - tan e tan e
Expert Solution
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Here we have described how the steps were done and generally what we do. Its a simple projectile motion but it makes unnecessary difficult for the student by adding one more angle means a plane which is making angle θ with our Cartesian coordinate. problem with CartesianAdvanced Physics homework question answer, step 1, image 1 coordinate is we have to do all our problems along our cartesian axis only. thats why so much difficulty with handling of angles.

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