I Review | ConstantsA3.80 mm diameter wire carries a 15.2 A current when the electricfield is 8.60x 10-2 V/m.Part AWhat is the wire's resistivity?p= 6.42x10-8 2mSubmitPrevious AnswersCorrectCorrect answer is shown. Your answer 6.4167-10-8 = 6.4167x10-8 Qm was either rounded differently or used a different number of significant figures thanrequired for this part.Part BIf a battery voltage of 8.55 V is applied to this wire to produce this current, how long must it be??L= 994SubmitPrevious Answers Request AnswerX Incorrect; Try Again; 2 attempts remaining

Answered: A3.80 mm diameter wire carries a 15.2 A…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I Review | Constants
A3.80 mm diameter wire carries a 15.2 A current when the electric
field is 8.60x 10-2 V/m.
Part A
What is the wire's resistivity?
p= 6.42x10-8 2m
Submit
Previous Answers
Correct
Correct answer is shown. Your answer 6.4167-10-8 = 6.4167x10-8 Qm was either rounded differently or used a different number of significant figures than
required for this part.
Part B
If a battery voltage of 8.55 V is applied to this wire to produce this current, how long must it be?
?
L= 994
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 2 attempts remaining

Expert Solution

Step 1

Part A)

Let the radius of the cross-section of the wire be r, the area of the cross-section of the wire be A, the magnitude of the electric field applied be E, and the current flowing through the wire be I.

The value of resistivity of the wire is calculated by using the following equation.

In this case,

r = 1.90×10^-3 m

Substitute the required values in equation (1) to get the value of the resistivity of the material of the wire in the following way.

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