A3 meter long steel angle shown in the figure has a section thickness of12.7 millimeters and a cross sectional area of 4350 mm?.Formal;TL-(1-0,630b/a)M;(1zy.z=ly.y) + M,(4.z – Izy.-y)TmaksGab?Czab*G' 5²5için c = cz =:3 mvQМyTem = 50 MPa ve G = 77,2 GPaIt2tAFind the maximum torque T that can be applied.cos20 +Tysin2® , Oort =°oy, tan20, -O- dy*-dy sin20 + T„cos20 , Imakemin = ± (,) +r,%3DTmaks659,3 Nm946,5 Nm588,2 Nm798,4 Nm899,1 Nm

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A3 meter long steel angle shown in the figure has a section thickness of 12.7 millimeters and a cross sectional area of 4350 mm. Ten 50 MPa ve G= 77,2 GPa Find the maximum torque T that can be applied. O 6593 Nm O465 Nm S00.2 Nm O 7A Nm 99.1 Nm

A3 meter long steel angle shown in the figure has a section thickness of 12.7 millimeters and a cross sectional area of 4350 mm. Ten 50 MPa ve G= 77,2 GPa Find the maximum torque T that can be applied. O 6593 Nm O465 Nm S00.2 Nm O 7A Nm 99.1 Nm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Problem 1.1MA

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Buckling of columns

The column is described as a vertical member of the structure that carries an axial compressive load, and buckling is a lateral deformation of the column under the application of load.

Question

A3 meter long steel angle shown in the figure has a section thickness of
12.7 millimeters and a cross sectional area of 4350 mm?.
Formal;
TL
-(1-0,630b/a)
M;(1zy.z=ly.y) + M,(4.z – Izy.-y)
Tmaks
Gab?
Czab*G' 5²5için c = cz =:
3 m
vQ
Мy
Tem = 50 MPa ve G = 77,2 GPa
It
2tA
Find the maximum torque T that can be applied.
cos20 +Tysin2® , Oort =°oy, tan20, -
O- dy
*-dy sin20 + T„cos20 , Imakemin = ± (,) +r,
%3D
Tmaks
659,3 Nm
946,5 Nm
588,2 Nm
798,4 Nm
899,1 Nm

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