A250-m-wide river flows due east at a uniform speed of 4,3m/s. A boat with a speed of67m/s relative to the water leaves the south bank pointed in a direction 30° west of north.What are the (a) magnitude and (b) direction of the boat's velocity relative to the ground? (c) How long does the boat take to cross the river? The velacity of the boat relatve to the ground i . br = (6,7m/s) SIN(- 30°); + (6.7 m/s) Cos (- 30°) - 3,35m/s î + %3D 5.803 The velocity of the beat relatue to the ground is : Vog = V br + Vr Thus, @mognitude of Vbq is : Iubal = Vo,95)²+ Gi807 O The direction of Ybg is: Tan"/ 80.7°>Xincorect aNSweR VB.y X Than direction of V bg is : Fan tan-bgi | 9.30°CORRECT 518 • 75 auSwee -- Why used instead of tan'/ Vbgy) VogX -- 1s tan (Vbg x [Vogy Please explain in cleap, Complete detail how to know which to use. Thank you!

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Chapter1: Units, Trigonometry. And Vectors
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A250-m-wide river flows due east at a uniform speed of
4,3m/s. A boat with a speed of67m/s relative to the water leaves
the south bank pointed in a direction 30° west of north.What are
the (a) magnitude and (b) direction of the boat's velocity relative
to the ground? (c) How long does the boat take to cross the river?
The velacity of the boat relatve to the ground is.
br = (6,7m/s) SIN(- 30°); + (6.7 m/s) Cos (- 30°)
- 3, 35 m/s î +
%3D
5.803
The velocity of the baat relatue to the ground is :
Vog = V br + Vr
Thus,
3.35 m/s Î t 5,80 m/s ir 43m/s is Ö,5 m/s its.8om/s?
@mognitude of Vbq is:
Iubal = Vo,95)²+ Gi807
5.88m/s
%3D
O The direction of Ybg is:
Tan"/
tan-! (VBgY)
VB.y X
F0.7° >X incorect
anSweR
Than direction of V bg is :
Fan
tan-bgi
| 9.30°| CORRECT
518
• 15
Vbg y
auSwer
is tan Nbgx used instead of tan '/Vbgy
--
Why
used insteed of tan'/ Vbgy)2
VogX
[Vbgy
Please explain in cleap, Complete
de tail how to know which to use.
Thank you!
Transcribed Image Text:A250-m-wide river flows due east at a uniform speed of 4,3m/s. A boat with a speed of67m/s relative to the water leaves the south bank pointed in a direction 30° west of north.What are the (a) magnitude and (b) direction of the boat's velocity relative to the ground? (c) How long does the boat take to cross the river? The velacity of the boat relatve to the ground is. br = (6,7m/s) SIN(- 30°); + (6.7 m/s) Cos (- 30°) - 3, 35 m/s î + %3D 5.803 The velocity of the baat relatue to the ground is : Vog = V br + Vr Thus, 3.35 m/s Î t 5,80 m/s ir 43m/s is Ö,5 m/s its.8om/s? @mognitude of Vbq is: Iubal = Vo,95)²+ Gi807 5.88m/s %3D O The direction of Ybg is: Tan"/ tan-! (VBgY) VB.y X F0.7° >X incorect anSweR Than direction of V bg is : Fan tan-bgi | 9.30°| CORRECT 518 • 15 Vbg y auSwer is tan Nbgx used instead of tan '/Vbgy -- Why used insteed of tan'/ Vbgy)2 VogX [Vbgy Please explain in cleap, Complete de tail how to know which to use. Thank you!
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