10. Why is the problem wrong? What step did the student make a mistake on and what should have the step said instead. Problem (Find the solution(s) for the following equation):2x3 + 6x2 – 8x2x3 + 6x2 - 8x - 24 = 02(x3 + 3x2 – 4x – 12) = 02((x3 + 3x?)(-4x – 12)) = 02(x² (x + 3) – 4(x + 3)) = 02(x? (x + 3) – 4(x + 3)) = 02(x2 + 3)(x – 4) = 0(x2 + 3) = 0x2 = -3= 24Step 1:Step 2:Step 3:Step 4:Step 5:Step 6:Step 7:Step 8:Step 9 (solution):(x – 4) = 0x = 4X == tiV3x = 4

We have to find the solution and choose the wrong step

Math

Algebra

a

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

10. Why is the problem wrong? What step did the student make a mistake on and what should have the step said instead.

Problem (Find the solution(s) for the following equation):
2x3 + 6x2 – 8x
2x3 + 6x2 - 8x - 24 = 0
2(x3 + 3x2 – 4x – 12) = 0
2((x3 + 3x?)(-4x – 12)) = 0
2(x² (x + 3) – 4(x + 3)) = 0
2(x? (x + 3) – 4(x + 3)) = 0
2(x2 + 3)(x – 4) = 0
(x2 + 3) = 0
x2 = -3
= 24
Step 1:
Step 2:
Step 3:
Step 4:
Step 5:
Step 6:
Step 7:
Step 8:
Step 9 (solution):
(x – 4) = 0
x = 4
X =
= tiV3
x = 4

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