a.xk(n) = 28(n +1)+38(n) +58(n – 2); hk(n) = 28(n) – 48(n – 3) : - b. x₁ (n) = -28(n + 1) − 38(n − 1) +58(n − 2); x₂ (n) = 58(n) - 38(n + 1) + 28(n + 2) — 48(n − 1) +68(n − 3)
a.xk(n) = 28(n +1)+38(n) +58(n – 2); hk(n) = 28(n) – 48(n – 3) : - b. x₁ (n) = -28(n + 1) − 38(n − 1) +58(n − 2); x₂ (n) = 58(n) - 38(n + 1) + 28(n + 2) — 48(n − 1) +68(n − 3)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Determine convolution of the signals:
![a.xk(n)
= 28(n+1)+38(n) + 58(n − 2); hk(n) = 28(n) – 48(n – 3)
b.x₁ (n) = -28(n + 1) − 38(n − 1) +58(n − 2);
=
x₂ (n) = 58(n) — 38(n + 1) + 28(n + 2) − 48(n − 1) + 68(n − 3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63792d50-862a-477a-90e7-26b0e3ee6e5e%2Fb198b896-d804-4b4e-9607-4f5b1798e5b6%2Fy98hgm_processed.png&w=3840&q=75)
Transcribed Image Text:a.xk(n)
= 28(n+1)+38(n) + 58(n − 2); hk(n) = 28(n) – 48(n – 3)
b.x₁ (n) = -28(n + 1) − 38(n − 1) +58(n − 2);
=
x₂ (n) = 58(n) — 38(n + 1) + 28(n + 2) − 48(n − 1) + 68(n − 3)
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