A.find ig B. Then use current divison to find io 19-7 152 212 361 312-AL 40 in Series 1254+ 5·20=100/25=452 13-2 50. 452+62-1052 Resistance with ig=2 125V/102 = 19=12.5amps Current divison rule for io чол 10 = 19/A) = 12.5 (401) =10amps loamps (.24) = 2.4amps A-12.5amps B-2.4amps

A.find ig B. Then use current divison to find io 19-7 152 212 361 312-AL 40 in Series 1254+ 5·20=100/25=452 13-2 50. 452+62-1052 Resistance with ig=2 125V/102 = 19=12.5amps Current divison rule for io чол 10 = 19/A) = 12.5 (401) =10amps loamps (.24) = 2.4amps A-12.5amps B-2.4amps

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

I need help to make sure, I need to find ig and then use current division to find io did I do it correctly?

A.find ig
B. Then use current divison to find io
19-7 152
212
361 312-AL
40 in Series
1254+
5·20=100/25=452
13-2
50.
452+62-1052
Resistance with ig=2
125V/102 = 19=12.5amps
Current divison rule for io
чол
10 = 19/A) = 12.5 (401)
=10amps
loamps (.24)
= 2.4amps
A-12.5amps
B-2.4amps

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