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a.can someone explain to me why lines 4 and 5 have syntax errors int n = 5.0; double x = 2.0; n == x; x = n%x; if (n != 4) then x = 2.0*x;

a.can someone explain to me why lines 4 and 5 have syntax errors int n = 5.0; double x = 2.0; n == x; x = n%x; if (n != 4) then x = 2.0*x;

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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a.can someone explain to me why lines 4 and 5 have syntax errors

int n = 5.0;
double x = 2.0;
n == x;
x = n%x;
if (n != 4) then x = 2.0*x;

 

b. It is known that x and n are integers, where x has a value of -1 and n has a value of 5. What is the value
of the following expression?

!(++x || n) + 6 - (!n && n * (n < n)) I know this equals 6 but how do I work it out

 

C.(4pts, 1 each)Compute the values of the following expressions if x is 1, y is 4 and z is 14. Assume that
true relations have a value of 1 (I want to see how these problems are worked out)
1. x+5<=z-(x||z)-y 
2. z/y%z-6<=!y 
3. x>=1&&y==3+y||z<14 

4. x-!y-y<=z*z/6>y 

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