a.) xa[n] = (3j)-n (8[n+4] + [n 1] + [n - 4]) b.) x[n] (0.81)¹/2u[n + 1] c.) £c[n] = (16)-nun – 4 d.) xa[n] (0.7) cos (0.25mn)u[n] (Hint: Use the Euler identity to represent the cosine.) = =

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