A. x1 + 2x2 + 3x3 = -7 2x1 – 3x2 – 5x3 = 9 — 6х1 — 8x2 + Хз — — 22

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter1: Foundations
Section1.2: Integers
Problem 1.29TI: Subtract: (a) 64 (b) 6(4) (c) 64 (d) 6(4) .
Question

How to solve using Gaussian Elimination? 

A. x1 + 2x2 + 3x3 = -7
= -7
2х1 — Зх2 — 5хз — 9
-6x1 – 8x2 + x3 = -22
Transcribed Image Text:A. x1 + 2x2 + 3x3 = -7 = -7 2х1 — Зх2 — 5хз — 9 -6x1 – 8x2 + x3 = -22
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