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a. (x - y)y' – 2y + 3x + ; у(1) %3D 5 dy b. sinx dx +у cosx + 2xe' -3x? 3 (1 — х*е')- dy dx 2y' 4y с. у" dsy d. dx5 d3y 2. 2. dx3 d²y dy dx² 'dx-2y = 0 е. + y² cos(2t) = 0 ; y(0) = 1 f. ty' + 2ty – y³ = 0

a. (x - y)y' – 2y + 3x + ; у(1) %3D 5 dy b. sinx dx +у cosx + 2xe' -3x? 3 (1 — х*е')- dy dx 2y' 4y с. у" dsy d. dx5 d3y 2. 2. dx3 d²y dy dx² 'dx-2y = 0 е. + y² cos(2t) = 0 ; y(0) = 1 f. ty' + 2ty – y³ = 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Answer A, B and D only please

1. Compute the solution for the following differential equations a. (x – y)y' – 2y + 3x + = 0 =0; y(1) = 5 dy + y cos x+ 2xe - 3x² = (1 – x²e') dy b. sin x dx 2y' 4y c. d³y 2- sxp dx3 d'y d²y -3- 2y = 0 d. - 2 - dx2 е. + y? cos(2t) = 0 y(0) = 1 dt f. t'y' + 2ty – y3 = 0
Transcribed Image Text:1. Compute the solution for the following differential equations a. (x – y)y' – 2y + 3x + = 0 =0; y(1) = 5 dy + y cos x+ 2xe - 3x² = (1 – x²e') dy b. sin x dx 2y' 4y c. d³y 2- sxp dx3 d'y d²y -3- 2y = 0 d. - 2 - dx2 е. + y? cos(2t) = 0 y(0) = 1 dt f. t'y' + 2ty – y3 = 0
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