A. x² = y² + 1 3. A. 4. ( 5. 3) The solution of = 5, y(1) = 1 is. B. y2 2+1 A. y cie + c₂e6 A. A. y = ₁x + ₂x² 7. (^. 8. The integrating factor of xy' + 2y = is. C. ³ B. 2 ts) The general solution of y" + 5y' -6y = 0 is. B. y=c₁e-6 + c₂e A. e-t 9. (. -) The general solution of r²y" - 3xy' + 4y = 0 is. B. y = c₁r² + c₂r²ln(r) C. y=+ The radius of convergence of Σ1(-1)*3kk(x-4). B. 0 C. ∞0 D. 3 6. (s) The minimum radius of convergence of power series solution about = -2 of the ODE (x²-49)y" + 2xy' + y = 0.. A. 7 B. 8 5) The value of {} is. B. et 844 3) The value of L-¹} is. B. 2tet + et A. 3tet + et The value of L{u(t-2)} is. B. e²(++) C. y² = 2x² +1 A. e²(+²) - 10. (The equivalent form of Using unit step functions is 4) + 4 C. y = ce+c₂e-₂ 026 C. 6 C. u(t) C. 2te-t + et f(t) = - {₁an (1) D. 1²-x²=0. 03 D. B. u(t-3)(tan(t) - 4) + 4 D. y cez + cela D. y=2+2 D. 5 C. e(++) D. e² (-3+²) D. 8(t) D. 3te +et C. 4u(t-3) + tan(t)u(t-3)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Q 10 please
A. x² = y² +1
3.
A.
4. (
5.
A. y cie + c₂e6
3) The solution of = 5, y(1) = 1 is.
B. y2x2+1
A.
8.
A. y = ₁x + ₂x²
us) The general solution of y" + 5y' -6y = 0 is.
B. y cie-6 + c₂e
9. (
The integrating factor of xy' + 2y = is.
C. ³
B. 2
A. e-t
-) The general solution of r2y" - 3xy' + 4y = 0 is.
B. y cr² + c₂r²ln(r)
The radius of convergence of 1(-1)*3kk(x-4).
B. 0
C. 00
11. (
A. 3tet + et
D. 3
6. (s) The minimum radius of convergence of power series solution about r= -2 of the ODE
(x²-49)y" + 2xy' + y = 0..
A. 7
B. 8
s) The value of {} is.
B. et
844
3) The value of L-1{} is.
B. 2tet + et
A. 1
A. e²(+²)
-
C. y² = 2x² +1
The value of L{u(t-2)} is.
B. e²(++)
10. (The equivalent form of
Using unit step functions is
A. u(t-3) (tan(t) + 4) + 4
D. 4u(t-3)-tan(t)u(t-3)
C. ycie + c₂e-bx
f(t) =
C. y=+(2)
C. 6
The value of f tan(t)o(t-)dt
B. 0
C. u(t)
C. 2te-t + et
D. ²-x²=0.
0<t<3
D.
D. y cez + cela
C. ₂
D. y = 2+2
D. 5
C. e(++) D. e² (3+²)
D. 8(t)
- {ian (1)
tan(t) t>3
B. u(t-3)(tan(t)-4) +4 C. 4u(t-3) + tan(t)u(t-3)
D. 3te +et
D. √2
Transcribed Image Text:A. x² = y² +1 3. A. 4. ( 5. A. y cie + c₂e6 3) The solution of = 5, y(1) = 1 is. B. y2x2+1 A. 8. A. y = ₁x + ₂x² us) The general solution of y" + 5y' -6y = 0 is. B. y cie-6 + c₂e 9. ( The integrating factor of xy' + 2y = is. C. ³ B. 2 A. e-t -) The general solution of r2y" - 3xy' + 4y = 0 is. B. y cr² + c₂r²ln(r) The radius of convergence of 1(-1)*3kk(x-4). B. 0 C. 00 11. ( A. 3tet + et D. 3 6. (s) The minimum radius of convergence of power series solution about r= -2 of the ODE (x²-49)y" + 2xy' + y = 0.. A. 7 B. 8 s) The value of {} is. B. et 844 3) The value of L-1{} is. B. 2tet + et A. 1 A. e²(+²) - C. y² = 2x² +1 The value of L{u(t-2)} is. B. e²(++) 10. (The equivalent form of Using unit step functions is A. u(t-3) (tan(t) + 4) + 4 D. 4u(t-3)-tan(t)u(t-3) C. ycie + c₂e-bx f(t) = C. y=+(2) C. 6 The value of f tan(t)o(t-)dt B. 0 C. u(t) C. 2te-t + et D. ²-x²=0. 0<t<3 D. D. y cez + cela C. ₂ D. y = 2+2 D. 5 C. e(++) D. e² (3+²) D. 8(t) - {ian (1) tan(t) t>3 B. u(t-3)(tan(t)-4) +4 C. 4u(t-3) + tan(t)u(t-3) D. 3te +et D. √2
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