Q 10 please A. x² = y² +13.A.4. (5.A. y cie + c₂e63) The solution of = 5, y(1) = 1 is.B. y2x2+1A.8.A. y = ₁x + ₂x²us) The general solution of y" + 5y' -6y = 0 is.B. y cie-6 + c₂e9. (The integrating factor of xy' + 2y = is.C. ³B. 2A. e-t-) The general solution of r2y" - 3xy' + 4y = 0 is.B. y cr² + c₂r²ln(r)The radius of convergence of 1(-1)*3kk(x-4).B. 0C. 0011. (A. 3tet + etD. 36. (s) The minimum radius of convergence of power series solution about r= -2 of the ODE(x²-49)y" + 2xy' + y = 0..A. 7B. 8s) The value of {} is.B. et8443) The value of L-1{} is.B. 2tet + etA. 1A. e²(+²)-C. y² = 2x² +1The value of L{u(t-2)} is.B. e²(++)10. (The equivalent form ofUsing unit step functions isA. u(t-3) (tan(t) + 4) + 4D. 4u(t-3)-tan(t)u(t-3)C. ycie + c₂e-bxf(t) =C. y=+(2)C. 6The value of f tan(t)o(t-)dtB. 0C. u(t)C. 2te-t + etD. ²-x²=0.03B. u(t-3)(tan(t)-4) +4 C. 4u(t-3) + tan(t)u(t-3)D. 3te +etD. √2

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A. x² = y² + 1 3. A. 4. ( 5. 3) The solution of = 5, y(1) = 1 is. B. y2 2+1 A. y cie + c₂e6 A. A. y = ₁x + ₂x² 7. (^. 8. The integrating factor of xy' + 2y = is. C. ³ B. 2 ts) The general solution of y" + 5y' -6y = 0 is. B. y=c₁e-6 + c₂e A. e-t 9. (. -) The general solution of r²y" - 3xy' + 4y = 0 is. B. y = c₁r² + c₂r²ln(r) C. y=+ The radius of convergence of Σ1(-1)*3kk(x-4). B. 0 C. ∞0 D. 3 6. (s) The minimum radius of convergence of power series solution about = -2 of the ODE (x²-49)y" + 2xy' + y = 0.. A. 7 B. 8 5) The value of {} is. B. et 844 3) The value of L-¹} is. B. 2tet + et A. 3tet + et The value of L{u(t-2)} is. B. e²(++) C. y² = 2x² +1 A. e²(+²) - 10. (The equivalent form of Using unit step functions is 4) + 4 C. y = ce+c₂e-₂ 026 C. 6 C. u(t) C. 2te-t + et f(t) = - {₁an (1) D. 1²-x²=0. 03 D. B. u(t-3)(tan(t) - 4) + 4 D. y cez + cela D. y=2+2 D. 5 C. e(++) D. e² (-3+²) D. 8(t) D. 3te +et C. 4u(t-3) + tan(t)u(t-3)