Sections a, b, c please Question #6 (use the following to solve a, b, and c on the next page)Many people believe that the moon influences the actions of some individuals. A study of dementiapatients in nursing homes recorded various types of disruptive behaviors every day for 12 weeks. Dayswere classified as moon days if they were in a 3-day period centered at the day of the full moon. Foreach patient, the average number of disruptive behaviors was computed for moon days and for all otherdays. The hypothesis is that moon days will lead to more disruptive behavior.The data is a follows:Patient Moon Days Other Days Difference13.330.273.063.670.593.0832.670.322.3543.330.193.143.331.262.0763.670.113.5674.670.30.44.3782.672.27961.594.41103.732.684.330.6113.330.65120.670.69-0.02131.331.260.07140.330.230.380.11521.62The following EXCEL output is provided:Moon DaysOther DaysDifferenceMeanStandard ErrorMedianModeStandard Deviation|Sample VarianceKurtosisSkewnessRangeMinimumMaximumSumCount3.022 Mean0.386981235 Standard Error3.33 Median3.33 Mode0.589333333 Mean0.114872462 Standard Error2.4326666670.3770530682.68#N/A0.4 Median1.26 Mode1.498771878 Standard Deviation | 0.444899132 Standard Deviation2.246317143 Sample Variance0.189526931 Kurtosis-0.115869713 Skewness5.67 Range0.33 Minimum1.4603202522.1325352380.197935238 Sample Variance0.517112402 Kurtosis1.21114287 Skewness1.48 Range0.11 Minimum1.59 Maximum-0.584033447-0.5748083854.43-0.026 Maximum45.33 Sum15 Count4.418.84 Sum36.491515 Count a. What sort of test would you suggest to compare moon days to other days? WHY?wur's stefinyow the leah chanedb. What would the null and alternative hypotheses be?Conduct the test you suggest in question (a) above that corresponds to your hypotheses in (b). Usea = 0.05. SOLVE AND INTERPRET CLEARLY AND THOROUGHLY. YOU MUST REFERENCE THEС.CONTEXT OF THE PROBLEM.Lantan e dta .he sult fro al are shon bolowNOVASOLVETHEthed to theAT REFERENCLENEL

Given information: x¯1-x¯2=3.022-0.58933=2.43266667≈2.4327sx¯1-x¯2=1.460320252≈1.4603n=15α=0.05a) The test that we would suggest to compare moon days to other days is paired t test, because the subjects for the both the samples are same. Therefore we should use the dependent t-test i.e. paired t test. b) The null and alternate hypothesis would be: Null hypothesis: H0 : μDifference=0 Alternate hypothesis: H0 : μDifference>0c) This is one tailed test. The significance level is 0.05 and we will conduct a matched-pairs t-test of the null hypothesis. Use the sample data to calculate the standard deviation of the differences(s), the standard error (S.E) of the mean difference, the degrees of freedom(DF), and the t statistic test statistic(t). s=1.460320252≈1.4603S.E=sn=1.460315=0.377053068≈0.3771D.F=n-1=15-1=14 t=[(x1-x2)-D]S.E=2.43266667-00.377053=6.451789722≈6.45The P-value for this test is the probability that a t statistic having 14 degrees of freedom is greater than 6.45. P-value = P(t > 6.45) Use the excel formula, "=T.DIST.RT(6.45,14)" to determine the P-value. P-value = 0.0000076 Decision: Since the P-value (0.000) is less than the significance level (0.05), hence we have to reject the null hypothesis. Conclusion: From the above test we have sufficient evidence in the favor of the claim that moon days will lead to more disruptive behavior.

Math

Probability

a. What sort of test would you suggest to compare moon days to other days? WHY? alaw) wor's stay b. What would the null and alternative hypotheses be? Conduct the test you suggest in question (a) above that corresponds to your hypotheses in (b). Use a = 0.05. SOLVE AND INTERPRET CLEARLY AND THOROUGHLY. YOU MUST REFERENCE THE C. CONTEXT OF THE PROBLEM.