a. What is the pH of a buffer solution that is 0.18 M NH3 and 0.18 M NH? Ki for NH3 is 1.8 x 10-8. pH = b. What is the pH if 41 mL of 0.13 M hydrochloric acid is added to 425 mL of this buffer? pH =
a. What is the pH of a buffer solution that is 0.18 M NH3 and 0.18 M NH? Ki for NH3 is 1.8 x 10-8. pH = b. What is the pH if 41 mL of 0.13 M hydrochloric acid is added to 425 mL of this buffer? pH =
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Chapter1: Chemical Foundations
Section: Chapter Questions
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![Certainly! Below is the transcription and explanation suitable for an educational website.
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**Buffer Solution pH Calculation**
**a.** What is the pH of a buffer solution that is 0.18 M \( \text{NH}_3 \) and 0.18 M \( \text{NH}_4^+ \)? The \( K_b \) for \( \text{NH}_3 \) is \( 1.8 \times 10^{-5} \).
**pH =** [blank space for answer]
*Explanation:* To calculate the pH of the buffer solution, use the Henderson-Hasselbalch equation:
\[ \text{pH} = \text{pKa} + \log\left(\frac{[\text{base}]}{[\text{acid}]}\right) \]
**b.** What is the pH if 41 mL of 0.13 M hydrochloric acid is added to 425 mL of this buffer?
**pH =** [blank space for answer]
*Explanation:* When adding an acid to the buffer, the pH changes depending on the buffer capacity. Adjust the concentration of \( \text{NH}_3 \) and \( \text{NH}_4^+ \) in the Henderson-Hasselbalch equation to find the new pH. Consider the volume change due to the addition of the acid.
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This transcription provides a clear view of the problem and hints at the method needed to solve the questions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2d324e2-7a67-4e3d-bb22-9ad23fbeb72b%2F8cce6ac8-bdbd-49c2-bf78-9e793b264dd0%2Fi536snf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Certainly! Below is the transcription and explanation suitable for an educational website.
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**Buffer Solution pH Calculation**
**a.** What is the pH of a buffer solution that is 0.18 M \( \text{NH}_3 \) and 0.18 M \( \text{NH}_4^+ \)? The \( K_b \) for \( \text{NH}_3 \) is \( 1.8 \times 10^{-5} \).
**pH =** [blank space for answer]
*Explanation:* To calculate the pH of the buffer solution, use the Henderson-Hasselbalch equation:
\[ \text{pH} = \text{pKa} + \log\left(\frac{[\text{base}]}{[\text{acid}]}\right) \]
**b.** What is the pH if 41 mL of 0.13 M hydrochloric acid is added to 425 mL of this buffer?
**pH =** [blank space for answer]
*Explanation:* When adding an acid to the buffer, the pH changes depending on the buffer capacity. Adjust the concentration of \( \text{NH}_3 \) and \( \text{NH}_4^+ \) in the Henderson-Hasselbalch equation to find the new pH. Consider the volume change due to the addition of the acid.
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This transcription provides a clear view of the problem and hints at the method needed to solve the questions.
Expert Solution

Step 1
a.) To calculate pH, we would use Henderson Hasselbalch equation.
b.) First we need to calculate moles of all species. Then hydrochloric acid will react with basic part of buffer, so we need to write a reaction and draw ICE table to calculate the equilibrium moles of all species.
Then we can use Henderson Hasselbalch equation to calculate pH.
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