A. What are the best-case and worst-case asymptotic time-costs (e.g., O(1), O(n), O(²), O(2"), O(n!), etc.) of the method below, in terms of n (the number of elements in names)? // Returns true if the specified list of names // contains "Mickey Mouse"; returns false otherwise. boolean containsMickeyMouse (Collection names) { for (String name : names) { if (name.equals ("Mickey Mouse")) { return true; } } return false; } Best-case: Worst-case:

A. What are the best-case and worst-case asymptotic time-costs (e.g., O(1), O(n), O(²), O(2"), O(n!), etc.) of the method below, in terms of n (the number of elements in names)? // Returns true if the specified list of names // contains "Mickey Mouse"; returns false otherwise. boolean containsMickeyMouse (Collection names) { for (String name : names) { if (name.equals ("Mickey Mouse")) { return true; } } return false; } Best-case: Worst-case:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Similar questions

Write a recursive method, matchingParen (String str), that returns: true if str is a nesting of zero or more pairs of parentheses, like "())" or "((()". false if str is null, or if str has any character other than right or left parentheses, or if the right and left parentheses do not match. System.out.println( matchingParen( ) ); System.out.println( matchingParen( "(())" ) ); System. out.println( matchingParen( "(()))" ) ); System.out.println( matchingParen( "((x))" ) ); System.out.println( matchingParen( "()))") ); System.out.println( matchingParen( null ) ); //true //true //true //false //false //false Hint: You may check the first and last chars, and then recur on what's inside them. You may also find it easier to use a helper method.
The following recursive method called z is created. This method accepts two parameters: A string s, and an integer index The code in the method is: if (index == s.length()) return ""; <------ base case if(index % 2 == 0) return ""+ s.charAt(index) + z(s,index+1); <---- recursive call else return z(s,index+1); <----- recursive call What would be the output with the call: z("javajavajava",0);
Analyze errorIf (x < 100) && (x> 10)System.out.println(“x” is between 10 and 100”);
49, question is in java, thanks
change Summation Integers problem to Finding the minimumproblem. Make sure you properly wrote/updated all text messages, method names,and math calculations.Hint: You can use java.lang.Math.min() method.Example: System.out.printf("The min of the integers %4d and %4d and %4dis %7d\n", a, b, c, MinTest(a, b, c));
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change Summation Integers problem to Finding the minimumproblem. Make sure you properly wrote/updated all text messages, method names,and math calculations.Hint: You can use java.lang.Math.min() method.Example: System.out.printf("The min of the integers %4d and %4d and %4dis %7d\n", a, b, c,d MinTest(a, b, c,d)); fix below code structure
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