A. Use the equation to calculate the following: 2 NaOH(aq) + H,SO4(aq) → Na,SO4(aq) + 2 H,0(1) #1 - the moles N22SO4 produced from 3.6 mol H2SO4 #2 - the moles NaOH required to react with 2.50 L of 0.125 M H2SO4 #3 - the volume of 0.250 M H2SO4 needed to react with 25.5 mL of 0.750 M NAOH

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A: 1 mole of a substance contains 6.022×1023 molecules.

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Q: Could you explain how 111 would be the answer? (Limiting Factor in Stoichiometry)

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Q: What are the three types of stoichiometry problems?

A: ANSWERE IS DISCUSSED BELOW :

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.