(a). t²y" - 4ty' +6y=0, t>0; y₁(t) = t² Assume that y2 = v(t)y₁, using above approach with p(t) = −4/t, we have t²v" + (4t4t)v' = 0 v" =0 v = c₁t + C₂ = (c₁t + c₂) t²
(a). t²y" - 4ty' +6y=0, t>0; y₁(t) = t² Assume that y2 = v(t)y₁, using above approach with p(t) = −4/t, we have t²v" + (4t4t)v' = 0 v" =0 v = c₁t + C₂ = (c₁t + c₂) t²
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can you explain how to get this answer step by step using redution of order

Transcribed Image Text:(a). t²y" - 4ty' +6y=0, t>0; y₁(t) = t²
Assume that y2 = v(t)y₁, using above approach with p(t) = −4/t, we have
t²v" + (4t4t)v' = 0
v" =0 v = c₁t + C₂
= (c₁t + c₂) t²
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