A. The weight of 25 tablets of morphine sulfate (150 mg) is 3.075 g. If 0.3075 g was used in the assay and it required 10.3 ml of 0.023N NaOH to back titrate 25 ml of 0.021N H2SO4. Calculate the percent labeled amount of morphine sulfate. Each ml of 1N H2SO4 is equivalent to 758.83 mg of morphine sulfate

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A. The weight of 25 tablets of morphine sulfate (150 mg)
is 3.075 g. If 0.3075 g was used in the assay and it
required 10.3 ml of 0.023N NaOH to back titrate 25 ml of
0.021N H2SO4. Calculate the percent labeled amount of
morphine sulfate. Each ml of 1N H2SO4 is equivalent to
758.83 mg of morphine sulfatc
B. What would be the volume of 0.02N H2SO4 needed to
titrate 100 ml of paregoric if the sample contains 0.035 g
of morphine? Each ml of 0.02N H2SO4 is equivalent to
28.53 mg of morphine.
Transcribed Image Text:A. The weight of 25 tablets of morphine sulfate (150 mg) is 3.075 g. If 0.3075 g was used in the assay and it required 10.3 ml of 0.023N NaOH to back titrate 25 ml of 0.021N H2SO4. Calculate the percent labeled amount of morphine sulfate. Each ml of 1N H2SO4 is equivalent to 758.83 mg of morphine sulfatc B. What would be the volume of 0.02N H2SO4 needed to titrate 100 ml of paregoric if the sample contains 0.035 g of morphine? Each ml of 0.02N H2SO4 is equivalent to 28.53 mg of morphine.
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