A. The polynomial equations for the velocity and altitude of an air-bound object are given as under. h(t)=-0.15t + 10t³-120² +510t+700 v(t)= -0.45t³ +30²-480t +700 Write a program in C++ to determine the values of height h(t) and velocity v(t) for this air-bound object for the time values varying from t-0 to t-150 minutes with an increment of 5 seconds. The program displays the output in a three-column format as (t, h(t), v(t)). seconds Hint: Consider changing time from minutes to seconds first.
A. The polynomial equations for the velocity and altitude of an air-bound object are given as under. h(t)=-0.15t + 10t³-120² +510t+700 v(t)= -0.45t³ +30²-480t +700 Write a program in C++ to determine the values of height h(t) and velocity v(t) for this air-bound object for the time values varying from t-0 to t-150 minutes with an increment of 5 seconds. The program displays the output in a three-column format as (t, h(t), v(t)). seconds Hint: Consider changing time from minutes to seconds first.
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![A. The polynomial equations for the velocity and altitude of an air-bound object are given as under.
h(t)= -0.15t +10r³-120² +510t + 700
v(t)=-0.45t +30t²-480t +700
Write a program in C++ to determine the values of height h(t) and velocity v(t) for this air-bound object for the
time values varying from t=0 to t-150 minutes with an increment of 5 seconds. The program displays the output
in a three-column format as (t, h(t), v(t)).
seconds
Hint: Consider changing time from minutes to seconds first.
150 X 60](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68c40972-190c-4d4d-8a86-27c34113017a%2Fa52db0df-e59a-4b43-936b-7fb0066d2074%2Ftm4xebc_processed.png&w=3840&q=75)
Transcribed Image Text:A. The polynomial equations for the velocity and altitude of an air-bound object are given as under.
h(t)= -0.15t +10r³-120² +510t + 700
v(t)=-0.45t +30t²-480t +700
Write a program in C++ to determine the values of height h(t) and velocity v(t) for this air-bound object for the
time values varying from t=0 to t-150 minutes with an increment of 5 seconds. The program displays the output
in a three-column format as (t, h(t), v(t)).
seconds
Hint: Consider changing time from minutes to seconds first.
150 X 60
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