a. The mean of this distribution is b. The standard deviation is c. The probability that wave will crash onto the beach exactly 1.7 seconds after the person arrives is P(x = 1.7) = d. The probability that the wave will crash onto the beach between 1.5 and 3.9 seconds after the person arrives is P(1.5 1) - f. Find the maximum for the lower quartile. seconds.

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**Understanding Wave Crash Intervals Through Uniform Distribution**

In today's lesson, we will examine the intervals at which waves crash on the beach. Given that waves are crashing onto the beach every 4.5 seconds, we will observe the time from when a person arrives at the shoreline until a crashing wave is noted, which follows a Uniform Distribution from 0 to 4.5 seconds. All calculations will be rounded to four decimal places when necessary.

1. **Mean and Standard Deviation of Distribution**
   - a. The mean of this distribution is **\[ \mu \]**.
   - b. The standard deviation is **\[ \sigma \]**.

2. **Probability Calculations**
   - c. The probability that a wave will crash onto the beach exactly 1.7 seconds after a person arrives is:\[ P(x = 1.7) = \text{0} \]
   - d. The probability that a wave will crash onto the beach between 1.5 and 3.9 seconds after a person arrives is: \[ P(1.5 < x < 3.9) = \]
   - e. The probability that it will take longer than 1 second for the wave to crash onto the beach after a person arrives is: \[ P(x \geq 1) = \]

3. **Quartile Analysis**
   - f. Find the maximum for the lower quartile: **\[ Q_1 = \]** seconds.

**Visual Aids:**

- The graph depicts a uniform distribution ranging from 0 to 4.5 seconds.
- A horizontal axis represents time in seconds, while the vertical axis represents the probability density function.
- Various intervals of interest (like point probability, specific intervals, and quartile information) are marked on the graph.

**Formulas to Utilize:**

For a uniform distribution \( U(a, b) \):
   - Mean \( \mu = \frac{a + b}{2} \)
   - Standard deviation \( \sigma = \frac{(b - a)}{\sqrt{12}} \)
   - Probability for a range \( P(c < X < d) = \frac{d-c}{b-a} \)
Transcribed Image Text:**Understanding Wave Crash Intervals Through Uniform Distribution** In today's lesson, we will examine the intervals at which waves crash on the beach. Given that waves are crashing onto the beach every 4.5 seconds, we will observe the time from when a person arrives at the shoreline until a crashing wave is noted, which follows a Uniform Distribution from 0 to 4.5 seconds. All calculations will be rounded to four decimal places when necessary. 1. **Mean and Standard Deviation of Distribution** - a. The mean of this distribution is **\[ \mu \]**. - b. The standard deviation is **\[ \sigma \]**. 2. **Probability Calculations** - c. The probability that a wave will crash onto the beach exactly 1.7 seconds after a person arrives is:\[ P(x = 1.7) = \text{0} \] - d. The probability that a wave will crash onto the beach between 1.5 and 3.9 seconds after a person arrives is: \[ P(1.5 < x < 3.9) = \] - e. The probability that it will take longer than 1 second for the wave to crash onto the beach after a person arrives is: \[ P(x \geq 1) = \] 3. **Quartile Analysis** - f. Find the maximum for the lower quartile: **\[ Q_1 = \]** seconds. **Visual Aids:** - The graph depicts a uniform distribution ranging from 0 to 4.5 seconds. - A horizontal axis represents time in seconds, while the vertical axis represents the probability density function. - Various intervals of interest (like point probability, specific intervals, and quartile information) are marked on the graph. **Formulas to Utilize:** For a uniform distribution \( U(a, b) \): - Mean \( \mu = \frac{a + b}{2} \) - Standard deviation \( \sigma = \frac{(b - a)}{\sqrt{12}} \) - Probability for a range \( P(c < X < d) = \frac{d-c}{b-a} \)
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