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a. The compressor power (kW). ɔ. The mass flow rate of the water (kg/s). c. The nozzle exit velocity (m/s).

a. The compressor power (kW). ɔ. The mass flow rate of the water (kg/s). c. The nozzle exit velocity (m/s).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Air enters an isentropic compressor at 100 kPa, 30°C with a mass flow rate of 1.3 kg/s and is compressed to 4000 kPa at State 2, after which the hot compressed air passes through an evaporation tank where it vaporizes water. Water and air do not mix. Next, the air enters a nozzle that expands it back to the atmosphere at 100 kPa. At State 3 the air is 320°C, 4000 kPa. Liquid water at 25°C, 100 kPa enters the evaporator (State 5) at a steady rate and is vaporized to saturated vapor at 100 kPa that goes out into the surrounds. The entire system is adiabatic and operates at a steady state. The nozzle efficiency is 85%. The kinetic energy in/out of the compressor can be neglected and the kinetic energy entering the nozzle can be assumed zero. The pressure dependence of the enthalpy of the liquid water can also be ignored. Assume constant specific heat for the air with C, = 1.005 kJ/kg K and C, = 0.718 kJ/kg K. Find: a. The compressor power (kW). b. The mass flow rate of the water (kg/s). c. The nozzle exit velocity (m/s). d. If the temperature at the nozzle exit were 250 K (not the actual value), find the rate of entropy generation for the nozzle only (kW/K). air inlet at 1.3 kg/s 30°C, 100 kPa 1 Water vapor at Po = 100 kPa Compressor 6 T3- 320°C P: - 4000 kPa 2 4000 kPa nozzle 4 n= 0.85 100 kPa Water inlet Evaporation tank 25°C, 100 kPa
Transcribed Image Text:Air enters an isentropic compressor at 100 kPa, 30°C with a mass flow rate of 1.3 kg/s and is compressed to 4000 kPa at State 2, after which the hot compressed air passes through an evaporation tank where it vaporizes water. Water and air do not mix. Next, the air enters a nozzle that expands it back to the atmosphere at 100 kPa. At State 3 the air is 320°C, 4000 kPa. Liquid water at 25°C, 100 kPa enters the evaporator (State 5) at a steady rate and is vaporized to saturated vapor at 100 kPa that goes out into the surrounds. The entire system is adiabatic and operates at a steady state. The nozzle efficiency is 85%. The kinetic energy in/out of the compressor can be neglected and the kinetic energy entering the nozzle can be assumed zero. The pressure dependence of the enthalpy of the liquid water can also be ignored. Assume constant specific heat for the air with C, = 1.005 kJ/kg K and C, = 0.718 kJ/kg K. Find: a. The compressor power (kW). b. The mass flow rate of the water (kg/s). c. The nozzle exit velocity (m/s). d. If the temperature at the nozzle exit were 250 K (not the actual value), find the rate of entropy generation for the nozzle only (kW/K). air inlet at 1.3 kg/s 30°C, 100 kPa 1 Water vapor at Po = 100 kPa Compressor 6 T3- 320°C P: - 4000 kPa 2 4000 kPa nozzle 4 n= 0.85 100 kPa Water inlet Evaporation tank 25°C, 100 kPa
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