D. Suppose a random sample of 35 teenagers averaged 7.3 hours of sleep pernight. Assume the population standard deviation is 1.8 hours.(1) Calculate a 95% confidence interval for the mean.(ii) Calculate a 98% confidence interval for the mean. QUESTION FOURA. Suppose a certain retail store has customers whose ages are mormallydistributed such that u=37.5 years and 0=7.6 years.(i) Calculate the probability that a randomly chosen customer is younger than44 years old.(ii) Calculate the probability that a randomly chosen customer is between 46and 54 years old.ctrlB. Quality control programs often establish control limits that are three standarddeviations from the target mean of a process. If the mean of a sample taken fromthe process is within the control limits, the process is deemed to be satisfactory.A process is designed to filo bottles with 16 ounces of soda with standarddeviation of 0.5 ounces. Determine the control limits above and below the meanfor this process using a sample of size n=30.C. Assume that a teacher needs to grade 155 exams and the amount of time ittakes to grade each of the exams is a normally distributed population, with anaverage of 12 minutes per exam and standard deviation of4.minutes per exam.Calculate the probability that it will take an average of more than 10 minutes perexam to grade a random sample of 20 exams.

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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In a certain high school, the probability that a student drops out is 0.1, and the probability that a dropout gets a high-school equivalency diploma (GED) is 0.25. What is the probability that a randomly selected student gets a GED?
A survey showed that 83% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 18 adults are randomly selected, find the probability that at least 17 of them need correction for their eyesight. Is 17 a significantly high number of adults requiring eyesight correction? ... The probability that at least 17 of the 18 adults require eyesight correction is (Round to three decimal places as needed.)
The police have estimated that there are twelve major accidents per day on a particular 10-mile stretch of a national highway. Suppose the incidence of accidents is evenly distributed on this 10-mile stretch of the highway. a. Find the probability that there will be fewer than eight major accidents in this 10-mile stretch of the highway. (Do not round intermediate calculations. Round your final answer to 4 decimal places.) Probability b. Find the probability that there will be more than two accidents in a 1-mile stretch of this highway. (Do not round intermediate calculations. Round your final answer to 4 decimal places.) Probability
A survey conducted on students of XYZ University reported the number of male and female students and their majors. The data obtained are given in the following table. Science Politics Total Men 109 13 122 Women 10 23 33 Total 119 36 155 a. What is the probability that a student majors in Science?b. What is the probability that a student majoring in Science of or being a male?c. What is the probability that a student majoring in Sciences and is given that he is a man?
You are a doctor ,a and on average you meet with 30 patients per day. Assuming the NHANES dataset is representative of your patient population, calculate the following. 1. The probability of a single individual having health insurance. = 0.8807812125569134 2. The probability that 3 people in a row will not have health insurance. 3. The probability that 1/3 of your 30 patients for the day do not have health insurance
In an election, suppose that 55% of voters support a new tax on fast food. If we poll 123 of these voters at random, the probability distribution for the proportion of the polled voters that support a new tax on fast food can be modeled by the normal distibution pictured below. Complete the boxes accurate to two decimal places.
Suppose that a screening test diagnoses 97% of sick people positive and 95% of healthy people negative. Assume that 7% of those screened are sick. If a screened person is chosen at random, then the probability of having a positive diagnosis is: O a. 0.0184 O b. 0.886 Oc. 0.406 O d. 0.594 O e. 0.114 Next p vity Jump to.. 2021
Based on a Comcast survey, there is a 0.8 probability that a randomly selected adult will watch prime-time TV live, instead of online, on DVR, etc. Assume that seven adults are randomly selected. Find the probability that fewer than three of the selected adults watch prime-time live. OA. 0.00430 B. 0.000358 OC. 0.0512 O D. 0.00467
Answer A-C
In an election, suppose that 35% of voters support a school levy increase. If we poll 220 of these voters at random, the probability distribution for the proportion of the polled voters that support a school levy increase can be modeled by the normal distibution pictured below. Complete the boxes accurate to two decimal places .
40% of consumers believe that cash will be obsolete in the next 20 years. Assume that 6 consumers are randomly selected. Find the probability that fewer than 3 of the selected consumers believe that cash will be obsolete in the next 20 years. The probability is (Round to three decimal places as needed.) ...
The table below shows the results of a survey that asked 2853 people whether they are involved in any type of charity work. A person is selected at random from the sample. Complete parts (a) through (d). Occasionally Frequently 223 Not at all Total Male 453 793 1469 Female 205 430 749 1384 Total 428 883 1542 2853 (a) Find the probability that the person is frequently or occasionally involved in charity work. P(being frequently involved or being occasionally involved) = 0.460 (Round to the nearest thousandth as needed.) (b) Find the probability that the person is female or not involved in charity work at all. P(being female or not being involved) = (Round to the nearest thousandth as needed.)

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