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A. Solve the following initial value problem: with y(5) = tan(5). (Find y as a function of t.) y = tan(t) B. On what interval is the solution valid? (Your answer should involve pi.) Answer: It is valid for -(pi/2)

A. Solve the following initial value problem: with y(5) = tan(5). (Find y as a function of t.) y = tan(t) B. On what interval is the solution valid? (Your answer should involve pi.) Answer: It is valid for -(pi/2)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please explain clearly part b)

A. Solve the following initial value problem: with y(5) =tan(5). (Find y as a function of t.) y = tan(t) B. On what interval is the solution valid? (Your answer should involve pi.) Answer: It is valid for -(pi/2) <t< D. Similar to C, but for the right end. Answer: PINF cos(t) 2 dy dt 1 C. Find the limit of the solution as t approaches the left end of the interval. (Your answer should be a number or "PINF" or "MINF". "PINF" stands for plus infinity and "MINF" stands for minus infinity.) Answer: MINF
Transcribed Image Text:A. Solve the following initial value problem: with y(5) =tan(5). (Find y as a function of t.) y = tan(t) B. On what interval is the solution valid? (Your answer should involve pi.) Answer: It is valid for -(pi/2) <t< D. Similar to C, but for the right end. Answer: PINF cos(t) 2 dy dt 1 C. Find the limit of the solution as t approaches the left end of the interval. (Your answer should be a number or "PINF" or "MINF". "PINF" stands for plus infinity and "MINF" stands for minus infinity.) Answer: MINF
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