A. Show that Dean is wrong by fleshing out a truth table to find all rows in which AB + A'B' evaluates to 0, not 1. Circle these rows. B. By part (a), A'B' is clearly not the inverse of AB. Using DeMorgan’s law, express the inverse of AB as a Boolean expression bexp5b that is a sum of literals. C. Extend the truth table from part (a) to add columns for bexp5b and AB + bexp5b. All entries in the column for AB + bexp5b should have the value 1,
Dean thinks that AB + A'B' simplifies to 1 by the Inverse law.
A. Show that Dean is wrong by fleshing out a truth table to find all rows in which AB + A'B' evaluates to 0, not 1. Circle these rows.
B. By part (a), A'B' is clearly not the inverse of AB. Using DeMorgan’s law, express the inverse of AB as a Boolean expression bexp5b that is a sum of literals.
C. Extend the truth table from part (a) to add columns for bexp5b and AB + bexp5b. All entries in the column for AB + bexp5b should have the value 1, showing that bexp5b is indeed the inverse of AB.
According to the the questions "Dean thinks that AB + A'B' simplifies to 1 which implies inverse law
As the Inverse law for Boolean algebra can be stated as follows:
For any Boolean expression X and its inverse Y which satisfies the following condition:
X + Y = 1
So as per Dean here X is AB and Y is A'B'
Let try to find that Dean statement is correct or not in Part A .
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