a. Locate the 95% prediction interval for driving accuracy (y) on the printout, and give a practical interpretation of the result. b. Locate the 95% confidence interval for mean driving accuracy (y) on the printout, and give a practical interpretation of the result. c. If you are interested in knowing the average driving accuracy of all golfers who have a driving distance of 300 yards, determine which of the intervals is relevant. Explain.
a. Locate the 95% prediction interval for driving accuracy (y) on the printout, and give a practical interpretation of the result. b. Locate the 95% confidence interval for mean driving accuracy (y) on the printout, and give a practical interpretation of the result. c. If you are interested in knowing the average driving accuracy of all golfers who have a driving distance of 300 yards, determine which of the intervals is relevant. Explain.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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a. Locate the 95% prediction interval for driving accuracy (y) on the printout, and give a practical interpretation of the result.
b. Locate the 95% confidence interval for
c. If you are interested in knowing the average driving accuracy of all golfers who have a driving distance of 300 yards, determine which of the intervals is relevant. Explain.

Transcribed Image Text:### Driving Performance Analysis Using a Straight-Line Model
A group of researchers developed a new method for ranking the total driving performance of golfers on a tour. The method requires knowing a golfer's average driving distance (yards) and driving accuracy (percent of drives that land in the fairway). They construct a straight-line model relating driving accuracy (y) to driving distance (x). A MINITAB printout with prediction and confidence intervals for a driving distance of x = 300 is shown below.
#### Data Table
##### MINITAB Output
**Predicted Values For New Observations:**
| New Obs | Fit | SE Fit | 95% CI | 95% PI |
|---------|--------|--------|-------------------|--------------------|
| 1 | 61.305 | 0.367 | (60.562, 62.048) | (56.716, 65.894) |
**Values of Predictors for New Observations:**
| New Obs | DISTANCE |
|---------|----------|
| 1 | 300 |
**Explanation of the Data:**
- **Predicted Values For New Observations:** For a driving distance (x) of 300 yards, the predicted driving accuracy (y) is 61.305.
- **Fit:** The predicted value of driving accuracy.
- **SE Fit:** The standard error of the mean prediction.
- **95% CI:** The 95% Confidence Interval for the predicted value, indicating that we can be 95% confident that the true mean value of driving accuracy for a driving distance of 300 yards lies between 60.562 and 62.048.
- **95% PI:** The 95% Prediction Interval, which indicates the range in which we can expect to find the individual driving accuracy for a driving distance of 300 yards 95% of the time. The interval is from 56.716 to 65.894.
- **Values of Predictors for New Observations:** Shows the value of the driving distance (x) used in the prediction, which is 300 yards in this case.
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