a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of thecats and dogs.DogsCatsTotalOld4070110Young103040Total50100150Test-statisticsZ=-p)0.8-0.7/0.7333>|-0,=1. 3055P-ValueP – Value = 2 x P (Z > 1.3055)=2 x 0.0959=0. 1918ConclusionP-value 0.1918 is greater than the level of significance 0.05, therefore do not reject the nullhypotheses. null hypotheses is accepted. Therefore the probability of being old in dogs andcats is equal.Find the power test and how many animals should be included in the study to repeat the test with the samesignificance as calculated in part a and %20 more power than calculated ?

Name: a. In an animal shelter, 100 cats and 50 dogs are being accommodated.
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Description: a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of thecats and dogs.DogsCatsTotalOld4070110Young103040Total50100150Test-statisticsZ=-p)0.8-0.7/0.7333>|-0,=1. 3055P-ValueP – Value = 2 x P (Z > 1.3055)

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a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of cats and dogs. Dogs Cats Total Old 40 70 110 10 30 40 Young Total 50 100 150 Test-statistics Z= 08-0.7 0.7333x(1-0.7333)x(+)

a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of cats and dogs. Dogs Cats Total Old 40 70 110 10 30 40 Young Total 50 100 150 Test-statistics Z= 08-0.7 0.7333x(1-0.7333)x(+)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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