a. If a player bets $14 on the number 1, what is the player's expected value? The expected value is dollars. (Round to the nearest cent as needed.)

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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In the game of roulette, when a player gives the casino $14 for a bet on the number 1, the player has a probability of losing $14 and a probability of making a net gain of $490. (The prize is $504, but the
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player's $14 bet is not returned, so the net gain is $490.) If a player bets $14 that the outcome is an odd number, the probability of losing $14 is and the probability of making a net gain of $14 is (If a player
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bets $14 on an odd number and win, the player is given $28 that includes the bet, so the net gain is $14.) Complete parts (a) through (c) below.
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a. If a player bets $14 on the number 1, what is the player's expected value?
The expected value is dollars.
(Round to the nearest cent as needed.)
Transcribed Image Text:37 1 In the game of roulette, when a player gives the casino $14 for a bet on the number 1, the player has a probability of losing $14 and a probability of making a net gain of $490. (The prize is $504, but the 38 38 20 18 player's $14 bet is not returned, so the net gain is $490.) If a player bets $14 that the outcome is an odd number, the probability of losing $14 is and the probability of making a net gain of $14 is (If a player 38 bets $14 on an odd number and win, the player is given $28 that includes the bet, so the net gain is $14.) Complete parts (a) through (c) below. 38 a. If a player bets $14 on the number 1, what is the player's expected value? The expected value is dollars. (Round to the nearest cent as needed.)
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