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A. H,= 2 X1= 2 g/mol 0,= 2X16= 32 g/mol H,O= 2X1 + 1X16 =18 g/mol (use this later) B. Determine the number of moles of each. 300 g H2 1 mol H2 =150 mol H2 300 g O2 1 mol O2 =9.4 mol O2 2 g 32 g C. Determine which is limiting. (divide by the coefficient) The smaller value is limiting as it runs out first. Hydrogen (H,)> 150/ 2 = 75 Oxygen (O,)-> 9.4/1= 9.4 O. Now use the mole conversion to determine the number of moles of product that can be produced. 2 mol H,0 = 18.8 mol H,0 9.4 moles O, 1 mol O, Now convert moles to grams and you're done! 18 g H,0 = 338.4 g H,0 8.8 mol H2O 1 mol H,0

A. H,= 2 X1= 2 g/mol 0,= 2X16= 32 g/mol H,O= 2X1 + 1X16 =18 g/mol (use this later) B. Determine the number of moles of each. 300 g H2 1 mol H2 =150 mol H2 300 g O2 1 mol O2 =9.4 mol O2 2 g 32 g C. Determine which is limiting. (divide by the coefficient) The smaller value is limiting as it runs out first. Hydrogen (H,)> 150/ 2 = 75 Oxygen (O,)-> 9.4/1= 9.4 O. Now use the mole conversion to determine the number of moles of product that can be produced. 2 mol H,0 = 18.8 mol H,0 9.4 moles O, 1 mol O, Now convert moles to grams and you're done! 18 g H,0 = 338.4 g H,0 8.8 mol H2O 1 mol H,0

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Arial BIUA Normal text 11 E▼=▼三 /-X Determine uie molar mass or each substance invoived. A. H,= 2 X1= 2 g/mol 0,= 2X16= 32 g/mol H,O= 2X1 + 1X16 =18 g/mol (use this later) B. Determine the number of moles of each. 300 g H2 1 mol H2 =150 mol H2 300 g O2 1 mol O2 mol O, 2g 32 g C. Determine which is limiting. (divide by the coefficient) The smaller value is limiting as it runs out first. Hydrogen (H,)-> 150/ 2 = 75 Oxygen (O,) -> 9.4/1= 9.4 D. Now use the mole conversion to determine the number of moles of product that can be produced. 2 mol H,0 = 18.8 mol H,0 9.4 moles O, 1 mol O, E. Now convert moles to grams and you're done! 18 g H,0 = 338.4 g H,0 18.8 mol H20 1 mol H,0 MacBook Air
Transcribed Image Text:Arial BIUA Normal text 11 E▼=▼三 /-X Determine uie molar mass or each substance invoived. A. H,= 2 X1= 2 g/mol 0,= 2X16= 32 g/mol H,O= 2X1 + 1X16 =18 g/mol (use this later) B. Determine the number of moles of each. 300 g H2 1 mol H2 =150 mol H2 300 g O2 1 mol O2 mol O, 2g 32 g C. Determine which is limiting. (divide by the coefficient) The smaller value is limiting as it runs out first. Hydrogen (H,)-> 150/ 2 = 75 Oxygen (O,) -> 9.4/1= 9.4 D. Now use the mole conversion to determine the number of moles of product that can be produced. 2 mol H,0 = 18.8 mol H,0 9.4 moles O, 1 mol O, E. Now convert moles to grams and you're done! 18 g H,0 = 338.4 g H,0 18.8 mol H20 1 mol H,0 MacBook Air
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