**a. Analysis of Variance (ANOVA) Table Construction**Given the following information obtained from three normally distributed populations, construct an ANOVA table. *Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "F" to 3 decimal places.*- SSTR = 173.9- SSE = 2,616.8- c = 3 (Number of groups)- n₁ = n₂ = n₃ = 6 (Sample size per group)**ANOVA Table:**| Source of Variation | SS | df | MS | F | p-value ||---------------------|--------|-----|------|-------|---------|| Between Groups | | | | | 0.617 || Within Groups | | | | | || Total | | | | | |**b. Conclusion at the 10% Significance Level**What is the conclusion to the ANOVA test of mean differences?- ○ Do not reject H₀; we cannot conclude that some means differ.- ○ Reject H₀; we can conclude that some means differ.- ○ Do not reject H₀; we can conclude that some means differ.- ○ Reject H₀; we cannot conclude that some means differ.**Explanation:**The ANOVA table helps identify whether there are any statistically significant differences between the means of the groups. The p-value provided (0.617) suggests that at the 10% significance level, we fail to reject the null hypothesis (H₀). Therefore, we cannot conclude that there are differences among the group means at this significance level.

Given information: SSTR=173.9SSE=2616.8c=3n1=n2=n3=6p-value=0.617Level of significance (α)=0.10…

Answered: a. Given the following Information…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Patients with two kinds of diagnoses were randomly assigned to one of three types of therapy and the effectiveness of the therapy was measure a 1-to-15 scale (with a higher number indicating greater effectiveness). There were two patients per cell. Use the data available below to comple parts (a) through (d) below. Click the icon to view the data table. Click here to view page 1 of the table of cutoff values for the F distribution. Click here to view page 2 of the table of cutoff values for the F distribution. Click here to view page 3 of the table of cutoff values for the F distribution. Click here to view page 4 of the table of cutoff values for the F distribution (a) Carry out the analysis of variance (use the 0.05 significance level). Complete the analysis of variance table for the data set below. SS MS F Source Columns Rows Interaction Within Total (Round to two decimal places as needed.) Data Table Diagnosis I Diagnosis II Therapy A 5 1 7 Print Therapy B 7 12 Done Therapy C 4282…
Find the value of a, b, ..., f in the one-way ANOVA table below. SS df MS F Source 361.5 b 60.25 f Treatment a 21 d Error 821.7 e Total
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Think about doing an Independent-Measures ANOVA, Step 3. If the data are as follows, find the SS-between. GROUP 1 GROUP 2 GROUP 3 1 3 5 3 2 7 2 4 6 A) SS-between = 26.00 B) SS-between = 42.00 C) SS-between = 6.00 D) SS-between = 13.00
Suppose the value of a stock varies each day from $10.82 to $23.17 with a uniform distribution. Find the third quartile, i.e. , 75% of all days the stock is below what value ?
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You decide that you want to make sure your estimate from part a is correct. You go out and gather 10 simple random samples of 25 people in your school and calculate the proportion of students within each sample whose Amazon packages arrive within two business days of ordering. The proportion of customers that receive their packages within two days of ordering are given below. 0.70, 0.75, 0.6, 0.95, 0.90, 0.73, 0.87, 0.86, 0.92, 0.97 Explain why all of the sample proportions are not the same.
A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants. Sample mean Sample variance Sample standard deviation Plant 1 Atlanta 84 76 81 76 70 81 78 25.2 5.02 Plant 2 Plant 3 Dallas Seattle 72 74 72 74 70 88 75 42.8 6.54 60 64 62 68 76 66 66 32.0 5.66
Suppose we want to compare scores (which can take on any value within a specified range) at baseline and at follow-up for a given sample. Using the data in the table below, compute a 95% CI for the mean difference in scores. Subject ID Baseline Follow-Up 1 13 6 2 10 8 3 9 11 4 12 11 5 8 5
Women are recommended to consume 1870 calories per day. You suspect that the average calorie intake is larger for women at your college. The data for the 11 women who participated in the study is shown below: 1799, 1703, 2097, 2112, 1824, 1956, 2072, 2113, 1951, 1872, 2126 Assuming that the distribution is normal, what can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Họ: ?v Select an answer v H: ? vSelect an answer c. The test statistic (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ? f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... O The data suggest that the population mean calorie intake for women at your college is not significantly more than 1870 at a = 0.01, so there is insufficient evidence to conclude that the population mean calorie intake for women at your college is more than 1870. (Please show your…
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