a. Find the first four nonzero terms of the Taylor series for the given function centered at a. 13 OA. The first four nonzero terms are 13 In 5- 5 13 OB. The first four nonzero terms are -- 5 13 OD. The first four nonzero terms are - 5 Ο A. 13In 5+ Σ k=1 8 OC. 13 In 5+ 13 13 OC. The first four nonzero terms are 13 In 5+ (x-5)-(-5)² 5 50 OB. 13 In 5+ (-1)k.. k=0 ∞ b. Write the power series using summation notation. 13(-1)+1(x-5)k 13 5*(x-5)k 13(-1)k+1 K=0 5*(x-5)k ∞ + + 13 50 OD. 13 In 5+ (-1)k+1.13(x-5)k -(x-5)- 13 50 13 25(x - 5)²- (x-5)³. 26 (x-5)-125(x-² -5)². + + 13 (x-5)-375 (-5)²+ 26 125 39 125 13 375 x-5)³. (x-5)³. 13 2500 -(x-5)³.
a. Find the first four nonzero terms of the Taylor series for the given function centered at a. 13 OA. The first four nonzero terms are 13 In 5- 5 13 OB. The first four nonzero terms are -- 5 13 OD. The first four nonzero terms are - 5 Ο A. 13In 5+ Σ k=1 8 OC. 13 In 5+ 13 13 OC. The first four nonzero terms are 13 In 5+ (x-5)-(-5)² 5 50 OB. 13 In 5+ (-1)k.. k=0 ∞ b. Write the power series using summation notation. 13(-1)+1(x-5)k 13 5*(x-5)k 13(-1)k+1 K=0 5*(x-5)k ∞ + + 13 50 OD. 13 In 5+ (-1)k+1.13(x-5)k -(x-5)- 13 50 13 25(x - 5)²- (x-5)³. 26 (x-5)-125(x-² -5)². + + 13 (x-5)-375 (-5)²+ 26 125 39 125 13 375 x-5)³. (x-5)³. 13 2500 -(x-5)³.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Use the following information to complete parts a. and b. below.
f(x) = 13 In x, a=5
a. Find the first four nonzero terms of the Taylor series for the given function centered at a.
13
OA. The first four nonzero terms are 13 In 5-5 (x- -5)--
13
13
OB. The first four nonzero terms are - + (x-5)-
50
5
13
OC. The first four nonzero terms are 13 In 5+ -(x-5)-
5
13 13
OD. The first four nonzero terms are - + -(x-5)-
5 50
b. Write the power series using summation notation.
∞
Ο A. 13In 5+ Σ
k=1
∞
OB. 13 In 5+ (-1)k.
k=0
∞
O c. 13 In 5+ Σ
k=0
13(-1)+1(x-5)k
∞
13
5*(x-5)k
13(-1)k+1
5k (x-5)k
OD. 13 In 5+ (-1)k +1._13
13
25 (x-5)².
(x-5)k
26
125
-(x- - 5)² +
13
50
(x-5) +
13
375 (X-5)² +
26
125 (X-5)³.
39
125 (x-5)3
13
375
(x-5)³.
13
--(x-
2500
x-5)³.
(...
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