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a. Find h(k(- 2)) b. Find h(k(x)) c. Find k(h(- 2)) d. Find k(h(x)) 3. Consider the functions, m(x) = x² + 3x and p(x) = 2x + 5. %3D a. Find m(p(1)) b. Find m(p(x)) c. Find p(m(1)) d. Find p(m(x)) 4. Consider the functions b(x) = (r - 11' and c(r)

a. Find h(k(- 2)) b. Find h(k(x)) c. Find k(h(- 2)) d. Find k(h(x)) 3. Consider the functions, m(x) = x² + 3x and p(x) = 2x + 5. %3D a. Find m(p(1)) b. Find m(p(x)) c. Find p(m(1)) d. Find p(m(x)) 4. Consider the functions b(x) = (r - 11' and c(r)

Intermediate Algebra
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Functions
Section9.1: Relations And Functions
Problem 75PS
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**Problem Set on Functions** **2. Consider the functions, \( h(x) = 3x - 7 \) and \( k(x) = \frac{x + 7}{3} \):** a. Find \( h(k(-2)) \) b. Find \( h(k(x)) \) c. Find \( k(h(-2)) \) d. Find \( k(h(x)) \) --- **3. Consider the functions, \( m(x) = x^2 + 3x \) and \( p(x) = 2x + 5 \):** a. Find \( m(p(1)) \) b. Find \( m(p(x)) \) c. Find \( p(m(1)) \) d. Find \( p(m(x)) \) --- **4. Consider the functions \( b(x) = (x - 1)^2 \) and \( c(x) = \sqrt{x} + 1 \):** a. Find \( b(c(9)) \) b. Find \( b(c(x)) \) c. Find \( c(b(9)) \) d. Find \( c(b(x)) \)
Transcribed Image Text:**Problem Set on Functions** **2. Consider the functions, \( h(x) = 3x - 7 \) and \( k(x) = \frac{x + 7}{3} \):** a. Find \( h(k(-2)) \) b. Find \( h(k(x)) \) c. Find \( k(h(-2)) \) d. Find \( k(h(x)) \) --- **3. Consider the functions, \( m(x) = x^2 + 3x \) and \( p(x) = 2x + 5 \):** a. Find \( m(p(1)) \) b. Find \( m(p(x)) \) c. Find \( p(m(1)) \) d. Find \( p(m(x)) \) --- **4. Consider the functions \( b(x) = (x - 1)^2 \) and \( c(x) = \sqrt{x} + 1 \):** a. Find \( b(c(9)) \) b. Find \( b(c(x)) \) c. Find \( c(b(9)) \) d. Find \( c(b(x)) \)
Expert Solution
Step 1

In this question we will use basic of calculus i.e concept of composite function.

We will simply find the value of one function at the mentioned value of x and then we will put that value in another function to get the required value.

Solution of the above question is in the steps below.

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