**Statistics Homework: Confidence Intervals and Estimation**Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.**TInterval** (13.046, 22.15) \(\bar{x} = 17.598\) \(S_x = 16.01712719\) \(n = 50\)**a. Express the confidence interval in the format that uses the "less than" symbol.** Given that the original listed data use one decimal place, round the confidence interval limits accordingly.\[ \text{_____ Mbps} < \mu < \text{_____ Mbps} \] *(Round to two decimal places as needed.)***b. Identify the best point estimate of \(\mu\) and the margin of error.**The point estimate of \(\mu\) is \(\text{_____ Mbps.}\) *(Round to two decimal places as needed.)*The margin of error is \(E = \text{_____ Mbps.}\) *(Round to two decimal places as needed.)***c. In constructing the confidence interval estimate of \(\mu\), why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution?**- **A.** Because the sample is a random sample, the distribution of sample means can be treated as a normal distribution.- **B.** Because the population standard deviation is known, the normal distribution can be used to construct the confidence interval.- **C.** Because the sample size of 50 is greater than 30, the distribution of sample means can be treated as a normal distribution.*Click to select your answer(s).*

Name: **Statistics Homework: Confidence Intervals and Estimation**Refer to
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Description: **Statistics Homework: Confidence Intervals and Estimation**Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.**TInterval** (13.046, 22.15) \(\bar{x} = 17.598\)

Given : We have given that , Confidence interval =(13.046,22.15)Mean (x)=17.598Standard deviation Sx =16.01712719sample size (n)=50a) To express the confidence interval in the format of less than symbol 13.05 Mbps <μ < 22.15 Mbps b) To find point estimate and margin of error The sample mean x is point estimate of population mean μ . The point estimate of μ is 17.60 Mbps Margin of error is given by , α=1-0.95=0.05zα=z0.052=z0.025=1-0.025=0.975z0.052 =1.96Margin of error =critical value ×standard deviationMargin of error =1.96 × 16.01712719Margin of error =31.39356929 Answer : The margin of error in two decimal places is 31.40 Mbps c) In constructing the confidence interval estimate of μ it is not necessary that sample data appear from a population with a normal distribution . Answer : C) Because the sample size of 50 is greater than 30 ,the distribution of sample means can be treated as normal distribution .

Answered: a. Express the confidence interval in…

Math

Statistics

a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence inter limits accordingly. Mbps

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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