a. Determine the magnitude of the equivalent concentrated load and the location at which it acts to have the same effect on the simply supported beam as does the distributed loading, 70.5 Ib 2500- ft lb ft „where we measure x in ft.
a. Determine the magnitude of the equivalent concentrated load and the location at which it acts to have the same effect on the simply supported beam as does the distributed loading, 70.5 Ib 2500- ft lb ft „where we measure x in ft.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Transcription for Educational Website:**
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**Problem Statement:**
a. Determine the magnitude of the equivalent concentrated load and the location at which it acts to have the same effect on the simply supported beam as does the distributed loading,
\[ w(x) = \left[ \left( \frac{2500 \, \text{lb}^2}{\text{ft}^3} \right)^{0.5} \right] = \left[ (2500x)^{0.5} \right] \, \frac{\text{lb}}{\text{ft}} \]
where we measure \( x \) in ft.
*Diagram Explanation:*
The diagram displays a simply supported beam labeled from point A to point B with a length of 10 ft. There is a distributed load \( w(x) \) along the beam, represented by arrows pointing downwards. The axis beneath the beam shows the position variable \( x \).
b. Draw a Free Body Diagram of the beam in part A in which you replace the distributed loading with the equivalent concentrated load. Do not solve for reactions.
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In this task, students will calculate the magnitude of a concentrated load that equates to the given distributed load over the beam and locate where that concentrated load acts. They will also practice their skills in constructing Free Body Diagrams, a fundamental skill in structural analysis. The goal is not to determine the reactions but to effectively translate the distributed load to a concentrated form.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbf4a0e0b-2125-467b-b1bc-8bc81e995df8%2Fae1f6b24-db54-407a-b67e-d282b043ecee%2Fw9994fg.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website:**
---
**Problem Statement:**
a. Determine the magnitude of the equivalent concentrated load and the location at which it acts to have the same effect on the simply supported beam as does the distributed loading,
\[ w(x) = \left[ \left( \frac{2500 \, \text{lb}^2}{\text{ft}^3} \right)^{0.5} \right] = \left[ (2500x)^{0.5} \right] \, \frac{\text{lb}}{\text{ft}} \]
where we measure \( x \) in ft.
*Diagram Explanation:*
The diagram displays a simply supported beam labeled from point A to point B with a length of 10 ft. There is a distributed load \( w(x) \) along the beam, represented by arrows pointing downwards. The axis beneath the beam shows the position variable \( x \).
b. Draw a Free Body Diagram of the beam in part A in which you replace the distributed loading with the equivalent concentrated load. Do not solve for reactions.
---
In this task, students will calculate the magnitude of a concentrated load that equates to the given distributed load over the beam and locate where that concentrated load acts. They will also practice their skills in constructing Free Body Diagrams, a fundamental skill in structural analysis. The goal is not to determine the reactions but to effectively translate the distributed load to a concentrated form.
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